   Chapter 4, Problem 9PS

Chapter
Section
Textbook Problem

Chromium metal reacts with oxygen to give chromium(III) oxide, Cr2O3. (a) Write a balanced equation for the reaction. (b) What mass (in grams) of Cr2O3 is produced if 0.175 g of chromium metal is converted completely to the oxide? (c) What mass of O2 (in grams) is required for the reaction?

(a)

Interpretation Introduction

Interpretation:

A balanced equation should be written for the reaction of metallic Cr with oxygen forming Cr2O3.

Concept introduction:

• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
Explanation

Here chromium metal reacts with oxygen to give chromium (III) oxide,Cr2O3

For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.

Therefore according with law of conservation of mass, the balanced chemical equation for the given reaction is,

(b)

Interpretation Introduction

Interpretation:

The mass of Cr2O3 produced if 0.175g chromium metal is completely converted to the oxide has to be calculated.

Concept Introduction:

• The number of moles of any substance can be determined  using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Massofthesubstance(ingram)=Amountofthesubstance×Molarmassofthesubstance

(c)

Interpretation Introduction

Interpretation:

The mass of O2 required for the reaction has to be determined.

Concept Introduction:

• The number of moles of any substance can be determined  using the equation,

Numberofmole=GivenmassofthesubstanceMolarmass

• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• Massofthesubstance(ingram)=Amountofthesubstance×Molarmassofthesubstance

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