   # What mass of oxygen, O 2 , is required to completely combust 454 g of propane, C 3 H g ? What masses of CO 2 and H 2 O are produced? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4.1, Problem 1CYU
Textbook Problem
71 views

## What mass of oxygen, O2, is required to completely combust 454 g of propane, C3Hg? What masses of CO2 and H2O are produced?

Interpretation Introduction

Interpretation:

The mass of oxygen,O2which is required to completely react with 454g of propane, C3H8and the masses of CO2 and H2O produced should be determined.

Concept introduction:

Number of moles can be determined using the given formula,

Numberofmole=GivenmassofthesubstanceMolarmass

For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.

Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.

Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.

### Explanation of Solution

Balanced chemical equation for the combustion reaction of propane is,

C3H8(g)+5O2(g)3CO2(g)+4H2O(l)

The amount (moles) of propane available can be calculated by using the equation as follows,

Numberofmole=GivenmassofthesubstanceMolarmass= 454gC3H8×1molC3H844.10gC3H8=10.29molC3H8

Using the stoichiometric factor, the number of moles of oxygen required is calculated as follows,

nO2 =10.29molC3H8×5molO21molC3H8=51.45molO2

The mass of O2 required is,

Mass= 51.45molO2×32

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