   # Elixirs such as Atka-Seltzer use the reaction of sodium bicarbonate with citric acid in aqueous solution to produce a fizz: 3 NaHCO 3 ( a q ) + C 6 H 8 O 7 ( a q ) → 3 CO 2 ( g ) + 3 H 2 O ( l ) + Na 3 C 6 H 5 O 7 ( a q ) a. What mass of C 6 H 8 O 7 should be used for every 1.0 × 10 2 mg NaHCO 3 ? b. What mass of CO 2 ( g ) could be produced from such a mixture? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 109E
Textbook Problem
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## Elixirs such as Atka-Seltzer use the reaction of sodium bicarbonate with citric acid in aqueous solution to produce a fizz: 3 NaHCO 3 ( a q )   +  C 6 H 8 O 7 ( a q ) → 3 CO 2 ( g )   +   3 H 2 O ( l )   +  Na 3 C 6 H 5 O 7 ( a q ) a. What mass of C6H8O7 should be used for every 1.0 × 102 mg NaHCO3?b. What mass of CO2(g) could be produced from such a mixture?

(a)

Interpretation Introduction

Interpretation: The mass of C6H8O7 used for every 1.0×102mgNaHCO3 and the mass of CO2(g) that can be produced from the given mixture is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The mass of C6H8O7 used for every 1.0×102mgNaHCO3 .

### Explanation of Solution

Given

The stated chemical equation is,

3NaHCO3(aq)+C6H8O7(aq)3CO2(g)+3H2O(l)+Na3C6H5O7(g)

The given mass of NaHCO3 is 1.0×102mg(0.1g) .

Molar mass of NaHCO3 =Na+H+C+3O=(23+1+12+(3×16))g/mol=84g/mol

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=GivenmassofthesubstanceAtomicmassofthesubstance

Substitute the value of the given mass and the atomic mass of NaHCO3 in the above expression.

NumberofmolesofNaHCO3=0.1g84g/mol=1.2×103mol

According to the stated chemical equation,

3mol of NaHCO3 react with C6H8O7 =1mol

1mol of NaHCO3 reacts with C6H8O7 =(13)mol

1

(b)

Interpretation Introduction

Interpretation: The mass of C6H8O7 used for every 1.0×102mgNaHCO3 and the mass of CO2(g) that can be produced from the given mixture is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The mass of CO2(g) that can be produced from the given mixture.

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