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ChemistryChemistry: An Atoms First Approach2nd Edition
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Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N 2 ( g ) + 3 H 2 ( g ) → 2NH 3 ( g ) a. What is the maximum mass of ammonia that can be produced from a mixture of 1.00 × 10 3 g N 2 and 5.00 × 10 2 g H 2 ? b. What mass of which starting material would remain unreacted?

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

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Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 117E
Textbook Problem
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Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation:

N 2 ( g )   +   3 H 2 ( g ) → 2NH 3 ( g )

a. What is the maximum mass of ammonia that can be produced from a mixture of 1.00 × 103 g N2 and 5.00 × 102 g H2?

b. What mass of which starting material would remain unreacted?

(a)

Interpretation Introduction

Interpretation: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen is to be calculated. The mass of the unreacted starting material is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Mass of the substance=(Number of moles)×(Molar mass of the substance)

To determine: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen.

Explanation of Solution

Given

The stated chemical reaction is,

N2(g)+3H2(g)→2NH3(g)

The given mass of N2 is 1.00×103 g .

The given mass of H2 is 5.00×102 g .

The molar mass of N2 =2N=(2×14) g/mol=28 g/mol

The molar mass of H2 =2H=(2×1) g/mol=2 g/mol

Formula

The number of moles of a substance is calculated by the formula,

Number of moles=Given mass of the substanceMolar mass of the substance

Substitute the value of the given mass and the molar mass of hydrogen and nitrogen in the above expression.

Number of moles of nitrogen=1.00×103 g28 g/mol=35.7 mol

Number of moles of hydrogen=5.00×102 g2 g/mol=250 mol

According to the stated reaction,

1 mol of N2 produces 2 mol of NH3

(b)

Interpretation Introduction

Interpretation: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen is to be calculated. The mass of the unreacted starting material is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Mass of the substance=(Number of moles)×(Molar mass of the substance)

To determine: The unreacted amount of the starting material.

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