   # Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N 2 ( g ) + 3 H 2 ( g ) → 2NH 3 ( g ) a. What is the maximum mass of ammonia that can be produced from a mixture of 1.00 × 10 3 g N 2 and 5.00 × 10 2 g H 2 ? b. What mass of which starting material would remain unreacted? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 117E
Textbook Problem
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## Ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation: N 2 ( g )   +   3 H 2 ( g ) → 2NH 3 ( g ) a. What is the maximum mass of ammonia that can be produced from a mixture of 1.00 × 103 g N2 and 5.00 × 102 g H2?b. What mass of which starting material would remain unreacted?

(a)

Interpretation Introduction

Interpretation: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen is to be calculated. The mass of the unreacted starting material is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen.

### Explanation of Solution

Given

The stated chemical reaction is,

N2(g)+3H2(g)2NH3(g)

The given mass of N2 is 1.00×103g .

The given mass of H2 is 5.00×102g .

The molar mass of N2 =2N=(2×14)g/mol=28g/mol

The molar mass of H2 =2H=(2×1)g/mol=2g/mol

Formula

The number of moles of a substance is calculated by the formula,

Numberofmoles=GivenmassofthesubstanceMolarmassofthesubstance

Substitute the value of the given mass and the molar mass of hydrogen and nitrogen in the above expression.

Numberofmolesofnitrogen=1.00×103g28g/mol=35.7mol

Numberofmolesofhydrogen=5.00×102g2g/mol=250mol

According to the stated reaction,

1mol of N2 produces 2mol of NH3

(b)

Interpretation Introduction

Interpretation: The maximum amount of ammonia that can be produced from a mixture of a given amount of nitrogen and hydrogen is to be calculated. The mass of the unreacted starting material is to be calculated.

Concept introduction: The mass of a substance can be obtained by using the number of moles of the substance present and its molar mass. The formula used to calculate the mass of a given substance is,

Massofthesubstance=(Numberofmoles)×(Molarmassofthesubstance)

To determine: The unreacted amount of the starting material.

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