   Chapter 5, Problem 19P

Chapter
Section
Textbook Problem

A 0.20-kg stone is held 1.3 m above the top edge of a water well and then dropped into it. The well has a depth of 5.0 m. Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone-Earth system (a) before the stone is released and (b) when it reaches the bottom of the well. (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well?

(a)

To determine
The gravitational potential energy of the stone–Earth system before the stone is released.

Explanation

Given Info:

The mass of the stone is 0.20kg .

The height from the top edge of the water well to stone is 1.3m .

Formula to calculate the potential energy is,

PEi=mghi

• hi is the height from the top edge of the water well to stone
• m is the mass of stone
• g is acceleration due to gravity

Since, we consider h=0 at the top edge of the water well; the height to the top of water well is positive.

Substitute 0.20kg for m, 9.8m/s2 for g and 1

(b)

To determine
The gravitational potential energy of the stone–Earth system when it reaches bottom of well.

(c)

To determine
The change in potential energy of the system from release to reaching the bottom of the well.

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