   Chapter 5, Problem 48PS

Chapter
Section
Textbook Problem

A 9.36-g piece of platinum was heated to 98.6 °C in a boiling water bath and then dropped onto ice. (See Study Question 47.) When the metal’s temperature had dropped to 0.0 °C, it was found that 0.37 g of ice had melted. What is the specific heat capacity of platinum?

Interpretation Introduction

Interpretation:

The specific heat capacity of platinum has to be calculated.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1K.Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat Capacity,ΔT= change in temperature.

Explanation

Given,

Mass of the platinum is 0.37g

Heat absorbed =333J1g-ice×0.37g=123.2J

Heat is released by the metal=-123

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 