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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

A 9.36-g piece of platinum was heated to 98.6 °C in a boiling water bath and then dropped onto ice. (See Study Question 47.) When the metal’s temperature had dropped to 0.0 °C, it was found that 0.37 g of ice had melted. What is the specific heat capacity of platinum?

Interpretation Introduction

Interpretation:

The specific heat capacity of platinum has to be calculated.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1K.Energy gained or lost can be calculated using the below equation.

  q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat Capacity,ΔT= change in temperature.

Explanation

Given,

Mass of the platinum is 0.37g

Heat absorbed =333J1g-ice×0.37g=123.2J

Heat is released by the metal=-123

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