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College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

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BuyFindarrow_forward

College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem

While running, a person dissipates about 0.60 J of mechanical energy per step per kilogram of body mass. If a 60.-kg person develops a power of 70. W during a race, how fast is the person running? (Assume a running step is 1.5 m long.)

To determine
How fast the person is running.

Explanation

Given Info:

The mechanical energy dissipated per step per kilogram of body mass. is 0.60J .

The mass of the person is 60.0kg .

The power developed by the person is 70.0W

The running step is equal to 1.5m .

Consider ΔN is the number of steps taken by the person in a time Δt .

According to equation for power,

P=WtΔt

  • Wt is the total work done
  • Δt is the change in time

Thus,

P=WtΔt=Wsm(ΔNΔt)

  • Ws is the work per step per mass
  • m is the mass of the person

On re-arranging,

ΔNΔt=PWsm       (I)

The running speed of the person is,

v=ΔN

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