   # Describe how you would prepare 2.00 L of each of the following solutions. a. 0.250 M NaOH from solid NaOH b. 0.250 M NaOH from 1.00 M NaOH stock solution c. 0.100 M K 2 CrO 4 from solid K 2 CrO 4 d. 0.100 M K 2 CrO 4 from 1.75 M K 2 CrO 4 , stock solution ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 6, Problem 37E
Textbook Problem
928 views

## Describe how you would prepare 2.00 L of each of the following solutions.a. 0.250 M NaOH from solid NaOHb. 0.250 M NaOH from 1.00 M NaOH stock solutionc. 0.100 M K2CrO4 from solid K2CrO4d. 0.100 M K2CrO4 from 1.75 M K2CrO4, stock solution

(a)

Interpretation Introduction

Interpretation: To prepare 2.00L of each of the following solutions using volumetric principles

0.250 M NaOH from solid NaOH

Concept Introduction: Dilution is to save time and spaces in the laboratory, routinely used solutions are often purchased or ready in concentrated form (called stock solution).

Water is then added to achieve the molarity desired for a particular solution. This process is Called dilution.

M1V1= M2V2.

M1and V1 are the molarity and volume of the concentrated stock solution,

M2and V2 are the molarity and volume of the diluted solution you want to make.

### Explanation of Solution

Given,

Recorded the data from question

Volume of NaOH is = 2L

Molarity of NaOH is= 0.250 M

The volume of NaOH and Molarity of NaOH were recorded as shown above

The gram of NaOH solid is determined as follows,

We know that

Molecular weight of NaOH is: 40

(b)

Interpretation Introduction

Interpretation: To prepare 2.00L of each of the following solutions using volumetric principles

0.250 M NaOH from 1.00 M NaOH stock solution

Concept Introduction: Dilution is to save time and spaces in the laboratory, routinely used solutions are often purchased or ready in concentrated form (called stock solution).

Water is then added to achieve the molarity desired for a particular solution. This process is Called dilution.

M1V1= M2V2.

M1and V1 are the molarity and volume of the concentrated stock solution,

M2and V2 are the molarity and volume of the diluted solution you want to make.

(c)

Interpretation Introduction

Interpretation: To prepare 2.00L of each of the following solutions using volumetric principles

0.100 M K2CrO4 from solid K2CrO4

Concept Introduction: Dilution is to save time and spaces in the laboratory, routinely used solutions are often purchased or ready in concentrated form (called stock solution).

Water is then added to achieve the molarity desired for a particular solution. This process is Called dilution.

M1V1= M2V2.

M1and V1 are the molarity and volume of the concentrated stock solution,

M2and V2 are the molarity and volume of the diluted solution you want to make.

(d)

Interpretation Introduction

Interpretation: To prepare 2.00L of each of the following solutions using volumetric principles

0.100 M K2CrO4 from 1.75 M K2CrO4 stock solution

Concept Introduction: Dilution is to save time and spaces in the laboratory, routinely used solutions are often purchased or ready in concentrated form (called stock solution).

Water is then added to achieve the molarity desired for a particular solution. This process is Called dilution.

M1V1= M2V2.

M1and V1 are the molarity and volume of the concentrated stock solution,

M2and V2 are the molarity and volume of the diluted solution you want to make.

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