   Chapter 6, Problem 5P

Chapter
Section
Textbook Problem

Drops of rain fall perpendicular to the roof of a parked car during a rainstorm The drops strike the roof with a speed of 12 m/s, and the mass of rain per second striking the roof is 0.035 kg/s. (a) .Assuming the drops come to rest after striking the roof, find the average force exerted by the rain on the roof. (b) If hailstones having the same mass as the raindrops fall on the roof at the same rate and with the same speed, how would the average force on the roof compare to that found in part (a)?

(a)

To determine
The force exerted by the rain drop on the roof.

Explanation

Given info:

The mass of drop is 0.035kg/s .

The velocity of the drop is 12m/s .

The Formula to calculate the impulse imparted to the rain drop by roof is,

Irain¯=(Fav¯)Δt=(Δm)v¯f(Δm)v¯i

• Irain¯ is the impulse
• Fav¯ is the average force exerted on the drop
• Δt is the time of contact
• Δm is the change in mass
• v¯f is the final velocity of the drop
• v¯i is the initial velocity of the bullet

Rearrange the equation for the force

(b)

To determine
The force exerted by the hailstone on the roof.

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