   Chapter 6.CR, Problem 1CR ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

#### Solutions

Chapter
Section ### Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
1 views

# The length of the radius of a circle is 15 mm. The length of a chord is 24 mm. Find the distance from the center of the circle to the chord.

To determine

To find: The distance from the center of the circle to the chord.

Explanation

Theorem:

1) A radius that is perpendicular to a chord bisects the chord.

2) If a line through the centre of a circle bisects a chord other than a diameter, then it is perpendicular to the chord.

Calculation:

Given that the length of the radius of a circle is 15 mm.

The length of the chord is 24 mm.

Let O be the center of the circle and AB be a chord.

So, AB = 24 mm and OB = radius = 15 mm

The distance from the center of the circle to the chord = OP.

By theorem, OPAB.

So, ◿OAB is a right triangle.

By theorem, AP=PB or AB = 2AP = 2AB.

So, AP=12AB.

So, AP=PB=1224=12 mm

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Solve the equations in Exercises 126. 2(x21)x2+1x4x2+1x2+1=0

Finite Mathematics and Applied Calculus (MindTap Course List)

#### In Problems 47-50, rationalize the denominator of each fraction and simplify. 49.

Mathematical Applications for the Management, Life, and Social Sciences

#### In Exercises 47-52, find and simplify f(a+h)f(a)h(h0) for each function. 50. f(x) = 2x3 x2 + 1

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### Differentiate. y=(z2+ez)z

Single Variable Calculus: Early Transcendentals

#### True or False: is a convergent series.

Study Guide for Stewart's Multivariable Calculus, 8th 