   Chapter 8, Problem 57P

Chapter
Section
Textbook Problem

A 10.0-kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 10.0 m/s, determine (a) the translational kinetic energy of its center of gravity, (b) the rotational kinetic energy about its center of gravity, and (c) its total kinetic energy.

(a)

To determine
The translational kinetic energy of the center of gravity of the cylinder.

Explanation

Given info: The mass of the cylinder is 10.0kg and the speed of center of gravity of the cylinder is 10.0m/s .

Explanation:

The formula for the translational kinetic energy is,

KEt=12mvt2

• m is mass of the cylinder.
• vt is translational speed of the cylinder.

Substitute 10.0kg for m and 10.0m/s for vt to find KEt

(b)

To determine
The rotational kinetic energy of the center of gravity of the cylinder.

(c)

To determine
The total kinetic energy of the cylinder.

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