In Problems 33–42, solve each triangle using either the Law of Sines or the Law of Cosines.33. B = 20°, C = 75°, b = 5 34. A = 50°, B = 55°, c = 9 35. a = 6, b = 8, c = 9 36. a = 14, b = 7, A = 85° 37. B = 35°, C = 65°, a = 15 38. a = 4, c = 5, B = 55° 39. A = 10°, a = 3, b = 10 40. A = 65°, B = 72°, b = 7 41. b = 5, c = 12, A = 60° 42. a = 10, b = 10, c = 15
In Problems 33–42, solve each triangle using either the Law of Sines or the Law of Cosines.33. B = 20°, C = 75°, b = 5 34. A = 50°, B = 55°, c = 9 35. a = 6, b = 8, c = 9 36. a = 14, b = 7, A = 85° 37. B = 35°, C = 65°, a = 15 38. a = 4, c = 5, B = 55° 39. A = 10°, a = 3, b = 10 40. A = 65°, B = 72°, b = 7 41. b = 5, c = 12, A = 60° 42. a = 10, b = 10, c = 15
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter2: Parallel Lines
Section2.6: Symmetry And Transformations
Problem 26E: Considering that the consecutive dials on the natural gas meter rotate in opposite directions, what...
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In Problems 33–42, solve each triangle using either the Law of Sines or the Law of Cosines.
33. B = 20°, C = 75°, b = 5
34. A = 50°, B = 55°, c = 9
35. a = 6, b = 8, c = 9
36. a = 14, b = 7, A = 85°
37. B = 35°, C = 65°, a = 15
38. a = 4, c = 5, B = 55°
39. A = 10°, a = 3, b = 10
40. A = 65°, B = 72°, b = 7
41. b = 5, c = 12, A = 60°
42. a = 10, b = 10, c = 15
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