The general solution to a differential equation is given by y = c1e^(3x) + c2x. Suppose we then impose the initial conditions y(0) = 1 and y'(0) = −1. What is the solution to the initial-value problem?

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The general solution to a differential equation is given by y = c1e^(3x) + c2x. Suppose we then impose the initial conditions y(0) = 1 and y'(0) = −1. What is the solution to the initial-value problem?

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