Psych 625 Statistics for the Behavior Sciences Entire Course

All Tutorials will be E-mailed immediately after the Payment, Please Check your inbox or Spam Folder and can also be downloaded by clicking on Tutorial Bucket.

7. Among freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100.

We know that +/- 1.96 standard deviations from the mean will contain 95% of the values. So, we can get the standard deviation by:

Directions: Use your graded tests and Unit 4 & 5 notes to answer the following questions. You can find the answers for #’s 1 – 62 on Exam 1 (3rd Nine Weeks Exam) and #’s 63 – 100 on your unit notes. Write your answers in the space provided, below each question.

a) Probability that it is a student = 800 / 1000 = 0.80 or 80%

(2) Give that a sample of 25 had x = 75, and (x-x)² = 48 the mean and standard

1. By hand, compute the mean, median, and mode for the following set of 40 reading scores:

Refer as needed to material in Chapters 12 and 13. Read the instructions carefully and answer all questions clearly and concisely. Include examples to highlight your comments.

The data sets for problems 5 and 6 can be found through the Pearson Materials in the Student Textbook Resource Access link, listed under Academic Resources. The data is listed in the data file named Lesson 20 Exercise File 1. Answer Exercises 5 and 6 based on the following research problem:

All Tutorials will be E-mailed immediately after the Payment, Please Check your inbox or Spam Folder and can also be downloaded by clicking on Tutorial Bucket.

Suppose that for a certain football game the probability that the home team will be

By looking at the table you see that it’s more freshman than the others school year level. The freshman have a percentage of 69.2. Senior have the lowest percentage which is 5.1. There was only 2 people

Females: 41.7 / 73.6 = 0.566576 = 56.7 %. The pass score of 56.7% shows that there is evidence of adverse impact: 62.5 / 77.7 = 0.8043758 = 80.4%. The pass rate which is 80.4% indicates that there is no evidence of adverse impact.

A standard score between 86-114 is considered to be within the average range with the average score being 100. A percentile rank between 16-84 is within the normal range with the average being 50. Percentile ranks indicate a persons standing relative to others the same age. E.g. a percentile rank of 20% performs as high as 20% of people the same age. It also indicates that 80% of people the same age earned higher scores (Wiig, Secord, & Semel, 2006).

Enter these results into your graphics calculator and determine the 5 figure summary for Steve’s 42 best test scores and the mean.