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The Voltage Estimation And The Resistance Of Thermistor

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Answer 1:

To measure the voltage estimation it need to find the resistance of thermistor.
For that value of R1=4852.96 ohms(From equation AeB/T) R2=4852.96 ohms R3=230 ohms R4=230 ohms

So according to equation:

V0= (R2/(R1+R2) –R4/(R4+R3) Vs (Lower value are double than upper)
V0 =(0.5-0.5) Vs
V0 =0

If the whetstone bridge circuit represent value 0 then the circuit is considered as the balance circuit and voltage across the circuit is zero. Which may be indicating that patient is suffering from the apnoea condition.

Answer 2:
a)
Information which are provided here are,
Voltage of the pulse= 5 V
Time duration T=1 ms
Frequency of the pulse=200 pulse/s
25 % energy consumption
Load resistance of 500 ohms.

Power require to stimulate,
The formula is = VIT= I2RT, Energy per pulse V=IR=I=V/R
= V2T/R
=(5)2(1)/500= O.O5 mJ.

Energy require per 200 pulses per second.
=0.05X200X60X60X24X365X10/1000
=3153600 J energy/10 year.
= 3153.600J energy/10 years

According to data the energy consumption by the battery is 25%
So the energy supplied by the battery is four-time grater:
So,
Eobtained= 4* Erequired =4*3153.600 =12614.4 KJ

Battery operation is not possible due to high energy and may cause rise in polarization and damage bladder tissues.

Answer:
b)

Two types of stimulator process are available. But two

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