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- #include <stdio.h>#include <stdlib.h>#include <string.h>#include <sys/types.h>#include <unistd.h>int main(int argc, char **argv){// the struct is used to ensure the loc variables are in the same order// without struct, compiler can swap these around making expolit impossiblestruct{char buffer[1024];volatile int changeme;} locals; locals.changeme = 0; if (argc != 2){printf("Uage: %s <input string>\n", argv[0]);return 1;}// copy argument to the bufferstrcpy(locals.buffer, argv[1]); // reveal the secret if "changeme" has been changed to 0xabcdabcdif (locals.changeme == 0xabcdabcd) setreuid(geteuid(), getegid());system("cat /home/q2/secret");}else{printf("Try again!\n");}exit(0);} ./run_me $(python -c 'print("A"*1024 + "\xcd\xab\xcd\xab")') running this script gives error try againDec2Hex function : def decimal_to_hex(number): hex_map = {0: '0', 1: '1', 2: '2', 3: '3', 4: '4', 5: '5', 6: '6', 7: '7', 8: '8', 9: '9', 10: 'A', 11: 'B', 12: 'C', 13: 'D', 14: 'E', 15: 'F'} hex_digits = [] while number > 0: hex_digits.append(hex_map[number % 16]) number //= 16 # Reverse the order of the hex digits and join them to form the final hex string hex_string = ''.join(reversed(hex_digits)) return f'0x{hex_string}' if hex_string else '0x0' Perform a Profile of your Dec2Hex function. Write a function that takes a timedate object as a parameter andcalculates the number of years from NOW to the time in the timedateobject. Add unit-testing code to your Dec2Hex exercise, and then perform aUnit test of the updated Dec2Hex code.C++ ---- (the bold is code)------ Consider the function interface below: bool isSame(int x, double y); Write a line of code that declares a pointer named Funprt that points to this function.
- 3."""Code _Write a function validSolution/ValidateSolution/valid_solution()that accepts a 2D array representing a Sudoku board, and returns trueif it is a valid solution, or false otherwise. The cells of the sudokuboard may also contain 0's, which will represent empty cells.Boards containing one or more zeroes are considered to be invalid solutions.The board is always 9 cells by 9 cells, and every cell only contains integersfrom 0 to 9. (More info at: http://en.wikipedia.org/wiki/Sudoku)""" # Using dict/hash-tablefrom collections import defaultdict def valid_solution_hashtable(board): for i in range(len(board)): dict_row = defaultdict(int) dict_col = defaultdict(int) for j in range(len(board[0])): value_row = board[i][j] value_col = board[j][i] if not value_row or value_col == 0: return False if value_row in dict_row: return False else: dict_row[value_row] += 1.Using C Language Define a struct student that stores the information about a student (name, age, GPA, semester). Write a function that accepts an array of students and returns the number of students with GPA greater than or equal 3.4.Plz paraphrase this code #include<iostream>using namespace std;struct studmodule{char modulename[30];int totalmarks;}; struct Student{char name[30];int age;int studid;struct studmodule module[4];float avgmarks;}stud[5]; float avg;float classavg;int highmark = 0;int lowmark = 0;float passrate = 0; void inputdata(){int i = 0, tot;cout<<"-------------------------------------------"<<endl;cout<<"Welcome to Technology College Muscut"<<endl;cout<<"-------------------------------------------"<<endl;cout<<"Students Personnel data Entry"<<endl;cout<<"-------------------------------------------"<<endl;for (i=0; i<5; i++){tot = 0;cout<<"Enter Student "<<i+1 << "Name :";cin>>stud[i].name;cout<<"Enter Student "<<i+1 << "Id Number :";cin>>stud[i].studid;cout<<"Enter Student "<<i+1 << "Age…
- create a c++ struct student which has student id, name and cgpa as members. create a static array of size 05 of type struct student. write a function input_record for taking record of 05 students. write a function display to print contents of array on output screen.C++ code NB: Pointers must be usedA1: File Handling with struct C++ This program is to read a given file and display the information about employees according to the type of employee. Specifically, the requirements are as follows. Read the given file of the information of employees. Store the information in an array or arrays. Display all the salaried employees first and then the hourly employees Prompt the user to enter an SSN and find the corresponding employee and display the information of that employee. NOTE : S- salaryemployee , H- Hourly employee S 135-25-1234 Smith Sophia DevOps Developer 70000H 135-67-5462 Johnaon Jacob SecOps Pentester 30 60.50S 252-34-6728 William Emma DevOps DBExpert 100000S 237-12-1289 Miller Mason DevOps CloudArchitect 80000S 581-23-4536 Jones Jayden SecOps Pentester 250000S 501-56-9724 Rogers Mia DevOps Auditor 90000H 408-67-8234 Cook Chloe DevOps QAEngineer 40 45.10S 516-34-6524 Morris Daniel DevOps ProductOwner 300000H 526-47-2435 Smith Natalie DevOps…
- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…C CodeApproved Libraries:<stdio.h><math.h><stdlib.h><time.h> (for srand(time(0)) only)C CodeApproved Libraries: <stdio.h><math.h><stdlib.h><time.h> (for srand(time(0)) only)