Modify the swap_string function in this task6.c to swap two strings. task6.c Swapping string Only modify swap_string() function and swap_string() call in the main, nothing else should be changed. */ #include #include void swap_string(char *s1, char *s2){ char *tmp = s1; s1=s2; s2=tmp; return; } int main() { char *string1 = "UNIX rules!"; char *string2 = "Windows drools!"; swap_string(string1, string2); printf("String 1: %s\n", string1); printf("String 2: %s\n", string2); return0; }
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Modify the swap_string function in this task6.c to swap two strings.
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- # Create a list of tuplestuples = [("p", 1), ("q", 2), ("r", 3)]# Use enumerate() to iterate over the tuples and print the index and valuefor index, value in enumerate(tuples):print(index, value)This code will print the following output:0 p1 q2 r Could you try to modify your code to get the output mentioned by you? Also, the output for the above function should be0 ('p', 1)1 ('q', 2)2 ('r', 3) Could you please confirm?Can you fix the code of the completion time based on the gantt chart and the output of the completion time must be the same in the image below? Thank you!Code: #include <iostream>#include <queue>#include <string>#include <vector> struct Process { int processId; int burstTime; int priority;}; void print_gantt_chart(const std::vector<std::pair<int, int>>& gantt_chart) { std::cout << "Gantt Chart:" << std::endl; std::cout << "----------------------------------------------------------------------------" << std::endl; std::cout << "| "; for (const auto& process : gantt_chart) { std::cout << "P" << process.first << " | "; } std::cout << std::endl; std::cout << "----------------------------------------------------------------------------" << std::endl; std::cout << "0 "; int currentTime = 0; for (const auto& process :…Write a function MedianWithoutHL(ScoreList) that takes an unsorted list of n numbers as a parameter, discards the highest and the lowest numbers and return the median. You can assume the number of items in the list is between 0.0 and 9.9. To find the median from a list of items, you have tosort the list and find out the value of the item in the middle.Note: If the list has an odd number of items, the median is the value of the middle item. If the list has an even number of items, the median is the average of the two middle items.Sample Run #1:scoreList1 = [9.0, 9.0, 7.5, 8.0, 9.5, 6.5, 5.0, 7.0, 7.5, 8.5]print("The Original ScoreList: ", scoreList1)print(MedianWithoutHL(scoreList1))Output of Sample Run #1:The Original ScoreList: [9.0, 9.0, 7.5, 8.0, 9.5, 6.5, 5.0, 7.0, 7.5, 8.5]The List after sorting: [5.0, 6.5, 7.0, 7.5, 7.5, 8.0, 8.5, 9.0, 9.0, 9.5]Without the High & Low: [6.5, 7.0, 7.5, 7.5, 8.0, 8.5, 9.0, 9.0]7.75
- I'm trying to delete a node after inputting data for 2-3 checks but the node I try to delete remains in the list. How do I fix my deleteCheck() function to run correctly with the rest of my code? Thank you. #include <stdio.h>#include <stdlib.h>// Austin Chong// The core concept of this assignment is to use a linked list in a C program.// 07 March 2020 struct checkNode{int checkNumber;char date[8];char paidTo[100];char description[100];double amount;struct checkNode *head;struct checkNode *next;}; struct checkNode *checkBook = NULL; /* Functions */ void addCheck(){int checkNumber;double amount;char temp;struct checkNode *newCheck = (struct checkNode*) malloc(sizeof(struct checkNode));printf("Please enter the check number: ");scanf("%d", &checkNumber);newCheck -> checkNumber = checkNumber;printf("Please enter the amount: ");scanf("%lf", &amount);newCheck -> amount = amount;printf("Please enter the date: ");scanf("%c", &temp);scanf("%[^\n]", newCheck ->…Can you fix the output of the Gantt chart in the code and the output of the gantt chart should be the same in the image below? Badly need to fix it :( Thank you! Code: #include <iostream>#include <queue>#include <string>#include <vector> struct Process { int processId; int burstTime; int priority;}; void print_gantt_chart(const std::vector<std::pair<int, int>>& gantt_chart) { std::cout << "Gantt Chart:" << std::endl; std::cout << "----------------------------------------------------------------------------" << std::endl; std::cout << "| "; for (const auto& process : gantt_chart) { std::cout << "P" << process.first << " | "; } std::cout << std::endl; std::cout << "----------------------------------------------------------------------------" << std::endl; std::cout << "0 "; int currentTime = 0; for (const auto& process :…PYTHON: Please fix my code to print the correct traversals, especially at the def functions, because I could not print the correct results of the inorder, postorder, and preorder traversals from the user input. #POSTORDERclass Node: def __init__(self, data): self.left = None self.right = None self.data = data # Insert Node def insert(self, data): if self.data: if data < self.data: if self.left is None: self.left = Node(data) else: self.left.insert(data) elif data > self.data: if self.right is None: self.right = Node(data) else: self.right.insert(data) else: self.data = data # Print the Tree def PrintTree(self): if self.left: self.left.PrintTree() print(self.data),…
- INT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function: void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support…Write a function that gets a linked list of ints, and reverses it. For example - on input 1 -> 2 -> 3 -> 4, after the function finishes the execution, the list becomes 4 -> 3 -> 2 -> 1 - If the list has one element, then it doesn’t change - If the list is empty, then it doesn’t change You may use the data fields in the struct and the functions provided in LL.h and LL.c. // reverses a linked list void LL_reverse(LL_t* list); Test for the Function; void test_q3() { LL_t* lst = LLcreate(); LL_add_to_tail(lst, 1); LL_add_to_tail(lst, 3); LL_add_to_tail(lst, 8); LL_add_to_tail(lst, 4); LL_add_to_tail(lst, 3); LL_reverse(lst); intcorrect[] = {3,4,8,3,1}; inti; node_t* n = lst->head; for(i=0;i<5;i++) { if (n==NULL) { printf("Q3 ERROR: node %d==NULL unexpected\n", i); return; } if (n->data != correct[i]) { printf("Q3 ERROR: node%d->data==%d, expected %d\n", i, n->data, correct[i]); return; } n = n->next; } if (n==NULL) printf("Q3 ok\n"); } Support File…
- In C++, you are going to write a program that implements a doubly linked list. The data must be read from the files and you can put the file names in your program. Letters.txt contains 26 English Letters: Copy the following exactly as it is into own .txt file to test: ABCDEFGHIJKLMNOPQRSTUVWXYZ Sequence.txt contains a list of numbers. Copy the following exactly as is into another .txt file3,-3,19,-19,18,1,-2,3,-18,17,1,-3,-13,14 You need to 1. Create a doubly linked list by reading the 26 letters from Letters.txt. 2. Sequence.txt file contains a sequence of relative letter positions. The initial position is at the beginning of the list which is ‘A’. The first number in the sequence is ‘3’. So the current position will move forward for three steps. Then the first letter to output is ‘D’ and now the current position is at ‘D’ as well. The second number in the sequence is ‘-3’. Then the second letter to output is the third element backward from the current position which is ‘A’. You…Implement the LPU Latch my code is written below having a lot of bugs in it please give you code with proper comments and remove the bugs having proper reason with correct code: #include <bits/stdc++.h> using namespace std; class LRUCache { list dq; unordered_map<int, list<int>::iterator> ma; int csize; public: LRUCache(int); void refer(int); void display(); }; LRUCache::LRUCache(int n) { csize; } void LRUCache::refer(int x) { if (ma.find(x) == ma.end()) { if (dq.size() = csize) { dq.pop_back(); ma.erase(last); } } else dq.erase(ma[x]); dq.push_front(x); ma[x] = dq.begin(); } void LRUCache::display() { for (auto it = dq.begin(); it = dq.end(); it+) cout << (it); cout << endl; } int main() { LRUCache ca(4); ca.refer(1); ca.refer(2); ca.refer(3); ca.refer(1); ca.refer(4); ca.refer(5); return 0; }Hi, I am implementing a matrox with several functions. I have pasted the error, the assignment and my code. Hopefully you can see what causes the error and how to fix it. Thank you so much. My transpose function gives an error: IndexError: list assignment index out of range self = <tests_matrix.TestsStudent testMethod=test_transpose> def test_transpose(self): self.assertEqual(str(self.a.transpose()), ' 1 4 7\n 2 5 8\n 3 6 9\n') self.assertEqual(str(self.b.transpose()), ' 2 8 14\n 4 10 16\n 6 12 18\n') self.assertEqual(str(self.c.transpose()), ' 1 0 0\n 0 1 0\n 0 0 1\n') self.assertEqual(str(self.a.transpose().transpose()), ' 1 2 3\n 4 5 6\n 7 8 9\n') self.assertEqual(str(self.e.transpose()), ' 0 0 0 1\n 0 0 1 0\n 0 1 0 0\n 1 0 0 0\n') > self.assertEqual(str(self.f.transpose()), ' 1 2 3 1\n 2 3 2 3\n 3 1 1 2\n') tests_matrix.py:34: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ self = 1 2 3 2 3 1 3 2 1 1 3 2 def transpose(self): nl…