0.002 m 1 d V = 200 turns Area = 2 x 104 m² h Area for sections other than bg = 5 x 104 m? = lgh = tha = 0.1 m, led Ina lab = log loc = e = 0.2 m %3D %3D ef = 0.099 m

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consider the ID as 12345678

0.002 m
1
V =
200 turns
3 Area =
2 x 104 m?
ン
h
Area for sections other than bg = 5 x 104 m?
= 0.2 m
lab
Iog = lgh = tha
%3D
%3D
= 0.1 m, lca
lef = 0.099 m
%3D
For the circuit magnetic circuit above find the value of I required to establish a flux in the gap of
Ax 10*Wb. (Where A being the last non zero digit of your ID. And the material of the core
depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is
between 5-8 use cast steel. If it is 0 or 9 use cast iron.). N=200turns.
Transcribed Image Text:0.002 m 1 V = 200 turns 3 Area = 2 x 104 m? ン h Area for sections other than bg = 5 x 104 m? = 0.2 m lab Iog = lgh = tha %3D %3D = 0.1 m, lca lef = 0.099 m %3D For the circuit magnetic circuit above find the value of I required to establish a flux in the gap of Ax 10*Wb. (Where A being the last non zero digit of your ID. And the material of the core depending on the last digit of your ID. If the last digit is between 1-4 use sheet steel. If it is between 5-8 use cast steel. If it is 0 or 9 use cast iron.). N=200turns.
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