0.030 moles of a weak acid, HA, was dissolved in 2.0 L of water to form a solution. At equilibrium, the concentration of HA was found to be 0.013 M. Determine the value of Ka for the weak acid. 1 2 Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms. Ка 3

Appl Of Ms Excel In Analytical Chemistry
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Chapter10: Potentiometry And Redox Titrations
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Question 2 of 16
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0.030 moles of a weak acid, HA, was dissolved in
2.0 L of water to form a solution. At equilibrium,
the concentration of HA was found to be 0.013 M.
Determine the value of Ka for the weak acid.
1
2
Based on your ICE table and definition of Ka, set
up the expression for Ka and then evaluate it. Do
not combine or simplify terms.
Ka =
5 RESET
[0]
[2.0]
[0.030]
[0.013]
[0.060]
[0.015]
[0.017]
[0.002]
[0.011]
[x]
[2x]
[0.030 + x]
[0.030 - x]
[0.015 + x]
[0.015 - x]
3 x 10-4
3 x 103
0.2
Transcribed Image Text:ll Verizon LTE 12:36 PM O 29% O Question 2 of 16 Submit 0.030 moles of a weak acid, HA, was dissolved in 2.0 L of water to form a solution. At equilibrium, the concentration of HA was found to be 0.013 M. Determine the value of Ka for the weak acid. 1 2 Based on your ICE table and definition of Ka, set up the expression for Ka and then evaluate it. Do not combine or simplify terms. Ka = 5 RESET [0] [2.0] [0.030] [0.013] [0.060] [0.015] [0.017] [0.002] [0.011] [x] [2x] [0.030 + x] [0.030 - x] [0.015 + x] [0.015 - x] 3 x 10-4 3 x 103 0.2
ll Verizon LTE
12:36 PM
O 29% O
Question 2 of 16
Submit
0.030 moles of a weak acid, HA, was dissolved in
2.0 L of water to form a solution. At equilibrium,
the concentration of HA was found to be 0.013 M.
Determine the value of Ka for the weak acid.
1
2
>
Based on the given values, fill in the ICE table to
determine concentrations of all reactants and
products.
НА(ag) +
H20(1)
= H3O*(aq) +
A (aq)
Initial (M)
Change (M)
Equilibrium
(M)
5 RESET
2.0
0.030
0.013
0.060
0.015
0.017
-0.017
0.002
-0.002
0.011
-0.011
+x
0.030 + x
-x
0.030 - x
0.015 + x
0.015 - x
Transcribed Image Text:ll Verizon LTE 12:36 PM O 29% O Question 2 of 16 Submit 0.030 moles of a weak acid, HA, was dissolved in 2.0 L of water to form a solution. At equilibrium, the concentration of HA was found to be 0.013 M. Determine the value of Ka for the weak acid. 1 2 > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. НА(ag) + H20(1) = H3O*(aq) + A (aq) Initial (M) Change (M) Equilibrium (M) 5 RESET 2.0 0.030 0.013 0.060 0.015 0.017 -0.017 0.002 -0.002 0.011 -0.011 +x 0.030 + x -x 0.030 - x 0.015 + x 0.015 - x
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