0.035x10-mol M of Ca2+. 0.012M 2.92x10-3L 0.07x10-mol Calculated Ksp 0.069x103 0.063x103 0.053x103 M of OH- 0.024M %3D 2.92x10-3L Ksp = (0.012)(0.024)(0.024) 0.069x103+0.063x103+0.053x10/3 =1.85x104 Average Ksp 1.85x104 Percent Error* 5.5 x 10-6 – 1.85 x 10-4 -97.02% x 100 on Ksp 1.85 x 10-4 • Consider that the actual value is 5.50 x 10 -6.

Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter5: Gases
Section: Chapter Questions
Problem 5.23PAE
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Hi, can you check my math? Can percent error be negative, if so what does that mean and how do I explain that for my results?  These are calculations for Determining the ksp of Calcium Hydroxide Lab.  Thanks!  

0.035x10-mol
M of Ca2+
0.012M
2.92x10-3L
0.07x10-3mol
Calculated Ksp
0.069x103
0.063x10-3
0.053x103
M of OH-
0.024M
2.92x10-3L
Ksp = (0.012)(0.024)(0.024)
0.069x10 3+0.063x103+0.053x10/3
Average Ksp
1.85x104
=1.85x104
Percent Error*
5.5 x 10-6 – 1.85 × 10-4
-97.02%
x 100
on Ksp
1.85 x 10-4
Consider that the actual value is 5.50 x 10 -6.
Transcribed Image Text:0.035x10-mol M of Ca2+ 0.012M 2.92x10-3L 0.07x10-3mol Calculated Ksp 0.069x103 0.063x10-3 0.053x103 M of OH- 0.024M 2.92x10-3L Ksp = (0.012)(0.024)(0.024) 0.069x10 3+0.063x103+0.053x10/3 Average Ksp 1.85x104 =1.85x104 Percent Error* 5.5 x 10-6 – 1.85 × 10-4 -97.02% x 100 on Ksp 1.85 x 10-4 Consider that the actual value is 5.50 x 10 -6.
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