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![0.0850 M F
(from 0.0850 NaF)
Ka for HF=7.20 x 10-4
[Solve First] Kb for F =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62bcb352-084d-49e3-8e2a-6ce439c7d9dd%2Fe141ac7e-127e-48e3-b3b3-41e221918f03%2Fobqiiei_processed.jpeg&w=3840&q=75)
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- I did an experiment: Molar concentration of Fe (NO3)3=.002 Molar concentration of NaSCN= .002 On my 1st trial: Volume of Fe(NO3)3 = 5 mL Moles of Fe3+, initial (mol) = 1 x 10-5 Volume of NaSCN (mL)= 1 mL Moles of SCN-,initial (mol)= 2 x 10-6 Absorbance was .08 Now trying to find Calculation of Kc I already found [FeNCS2+] equilibrium, from calibration curve (mol/L)= 2.25 x 10-5 Now I need to know: 1. moles FeNCS2+ at equilibrium (10mL) (mol) 2. moles Fe3+, reacted (mol) 3. moles Fe3+, equilibrium (mol) 4. [Fe3+] equilibrium, unreacted, 10 mL (mol/L) 5. moles SCN-, reacted (mol) 6. Moles SCN-, equilibrium (mol) 7. [SCN-] equilibrium (unreacted) 10 mL (mol/L) Feel free to just give me the formula to find these. Or to charge me 2 or 3 questions if I asked too much. Thank you!!!!!!I’m having trouble finding the Ka value can you please help how to get the answer?FYI: #5-8 is like a),b),c) and d) Thank you.
