0.10- Formic acid, HFor, has a Kvalue of 1.8 x 10-4. You need to prepare 150 mL of a buffer hav- ing a pH of 3.25 from 0.10 M HFor solution and a 0.10 M NaFor solution. How many mL of NaFor and HFor should be mixed to make the desired buffer? -4 -

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 57P
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Question 4 and 5

201×の-91X カbム
CN-] xHF]
[NOH
66.304 x10-6
%3D
メx7
%3D
メ-01
4. Formic acid, HFor, has a K value of 1.8 × 10-4. You need to prepare 150 mL of a buffer hav-
ing a pH of 3.25 from 0.10 M HFor solution and a 0.10 M NaFor solution. How many mL
of NaFor and HFor should be mixed to make the desired buffer?
mL HFO.
mL NaFor
LsatE]
(NaFor]
CHFOR]
5. When five drops of 0.10 M NaOH were added to 20 mL of the buffer in question 4, the pH
went from 3.25 to 3.31. Write a net ionic equation to explain why the pH did not go up more
than this.
Transcribed Image Text:201×の-91X カbム CN-] xHF] [NOH 66.304 x10-6 %3D メx7 %3D メ-01 4. Formic acid, HFor, has a K value of 1.8 × 10-4. You need to prepare 150 mL of a buffer hav- ing a pH of 3.25 from 0.10 M HFor solution and a 0.10 M NaFor solution. How many mL of NaFor and HFor should be mixed to make the desired buffer? mL HFO. mL NaFor LsatE] (NaFor] CHFOR] 5. When five drops of 0.10 M NaOH were added to 20 mL of the buffer in question 4, the pH went from 3.25 to 3.31. Write a net ionic equation to explain why the pH did not go up more than this.
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