0.185kg A 185 g object is attached to a spring that has a force constant of 75.5 N/m. The object is pulled 8.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless table. long A) How will it take the object to return to its original position, 8.25 cm to the right of equilibrium? B) What is the maximum speed max of the object? C) Find the locations of the object when its velocity is one-third of the maximum speed. Treat the equilibrium position as zero, positions to the right as positive, and positions to the left as negative. xrnig

Physics for Scientists and Engineers with Modern Physics
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Oscillatory Motion
Section: Chapter Questions
Problem 47AP: A particle with a mass of 0.500 kg is attached to a horizontal spring with a force constant of 50.0...
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A 185 g object is attached to a spring that has a force constant of 75.5 N/m. The object is
pulled 8.25 cm to the right of equilibrium and released from rest to slide on a horizontal,
frictionless table.
long
A) How will it take the object to return to its original position, 8.25 cm to the right of
equilibrium?
B) What is the maximum speed Vmax of the object?
C)
Find the locations of the object when its velocity is one-third of the maximum speed.
Treat the equilibrium position as zero, positions to the right as positive, and positions
to the left as negative.
tiong
Transcribed Image Text:any form 0.185k9 A 185 g object is attached to a spring that has a force constant of 75.5 N/m. The object is pulled 8.25 cm to the right of equilibrium and released from rest to slide on a horizontal, frictionless table. long A) How will it take the object to return to its original position, 8.25 cm to the right of equilibrium? B) What is the maximum speed Vmax of the object? C) Find the locations of the object when its velocity is one-third of the maximum speed. Treat the equilibrium position as zero, positions to the right as positive, and positions to the left as negative. tiong
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