0.25 m 25° B 0.5 m 1.5 m - 0.12 m 10 kN 5 m

Q: 40 kN 30 kN 20 kN 16 kN-m 24 kN/m 10 kN/m A 15 kN 3 m 4 m 2 m 4 m 2m 1.5 m

A: Loads acting on a beam is given. Dimensions at which loads acting and the magnitudes of the load are…

Q: A cable is loaded and supported as shown in Fig. The vertical distance yc is 4 ft. Determine The…

A:

Q: 0.8 1 0.8 m 0.8 m D 0.6 m E 1.2 m 1.2 m y F 1.2 m

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Q: 20 KN 10 KN 10KN/m 15KN/m 10 KN/m B. 1.00 1.00 2.00 1.00

A:

Q: Q/ The force in the member (CA) is 12m 50 ку. 10 points 5m 16x

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Q: 10 kN 5 kN 3 kN/m F C D E 3 m 1 m 4 m 3 m 1 m

A:

Q: Q/ The force in the member (CA) is 12m 50 ку 5m BX

A:

Q: Using unity conversion ratios, show that 1.00 lbm weighs 1.00 lbf on earth

A: →Mass of 1 lbm is subjected to standard earth gravity→ g = 32.174 ft/s2→From Newton's second lawW…

Q: 2 m C 2.5 m 125 mm 1.5 m 25 kN/m 2 m 4 m

A: To determine the reaction at A and B, the beam can be dealt in two sections that are AD and DB. In…

Q: 38.3 kN-m F) 23.3 kN-m G 8.3 kN-m H. 13.8 kN-m E.

A:

Q: 5 m A 30 kN B 5 m 5 m 5 m 5 m 20 KN 5 m 5 m E

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Q: 400 N 400 Ν 200 N [0.2 m 200 N - 3 m -2 m- 300 N 300 N

A: Couple moment generated due to the 200 N load on the beam is M200=-200×0.2=-40 N·m Negative sign…

Q: F1 = 5 kN F2 = 13 kN 0 = 45° B - 60° C F3 = 4 kN B 2 m 3. 7m F4 = 22 kN E lJa = 30° F5 = 4 kN

A: In case of multiple force on a system, resolve the forces in horizontal and vertical direction. This…

Q: H G 60 E D 7 kN 7 kN 9 kN 6m 6m 6m 6m

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Q: 12 kN.m 3 m 12 kN/m 1 m 12 kN.m 1 m 4 m 3 m 12 kN/m

A: The shear force and bending moment diagram has been drawn below.

Q: KIN 14 kN / m 10 kN / m A B ID 4 m 2.5 m 2.5 m 3 m

A: Finding support reactions:RA+RB=12*4*14+14*5+20+30RA+RB=148…

Q: 2 kN 2 kN 2 kN/m 3 kN/m B 3.5 m 15 m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: F1 = 5 kN F2 13 kN -30 C. F3 = 4 kN 45 A 2m 7 m 5n F4 = 22 kN a30° F5 = 4 kN

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Q: BM at B is 3 kN 1 m D 1m 1 m B 1 m A

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Q: 1. 500 N-m/sec to HP 2. 85 joules/sec to KWatt

A: Hi and thanks for the questions. Since you have asked questions with multiple sub-parts, we will…

Q: Find the force of the rods AB, AC, BC and BD. 20 N 30 N В 4m 4m 4m 4m 4m 4m A 4m E

A:

Q: 15 kN 10 kN/m 20 kN · m A 2 m 1m 1m 2 m What is the reaction force at A?

A: Given: Point load=15kN Moment=20kNm Uniform load=10kN/m

Q: 15 KN 10 KN 10 KN 20 KN E A 5.0m

A: To determine the support reaction at J.

Q: 100 kN 64 kN 82 kN 82 kN 55 kN 2m A 3 m 3m 3 m 3 m 3m 3 m 91 kN 73 kN 46 kN

A:

Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E

A: Let  RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…

Q: 6 m G m- m- 40KN 40KN 40KN

A:

Q: 2 tór/m 8 ton F 4 ton-m E 3 ton/m 2 m 4 m Im1m 2 m 2 m

A: According to the principal of engineering mechanics  Reaction and moment at support is equal to zero

Q: In each case, draw the shear and moment diagrams for the beam.

A: The free body diagram of the first beam is as follows: Calculate the force in the vertical…

Q: 1 m 1 m 30° b. 0.5 m 0.5 m b 1m -75 mm-

A: Given Data The mass of the drum is:m=20 kg The supported diamter of frame is :D=2mm Now draw the…

Q: 24 kN/m 64 kN • m D A B - 2 m -2 m

A: Let us draw the reaction force

Q: 80 kN 40 kN 60 kN -10 kN/m A B 2 mim. 3 m 3 m 2m 1 m (b) 10 k I k/ft B 12 8' (b)

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Q: A 1.20m 18 KN 0.75m 12 kN/m 1.20m B

A: The given is as shown below,

Q: F 105° 60° 45° 300 lb 60° 400 lb 200 lb

A:

Q: F = 120 lb | 30° 12 kN 1.25"- 30 4 m 1.5" 5 m 11"

A:

Q: 8 KN 3 AN/m 12 AN 6 KN/m BC D 2.0 m 1.0m 3.0 m 3.0 m

A: Apply the equilibrium condition of force in the vertical direction. Apply the equilibrium condition…

Q: 3m 6 m -3 m G 20 kN 15 kN H. B -3 m 3 m

A: given; ED=3mCE=4mCH=6mHF=4mFD=9mlets taking tension force in member BC=TBClets taking tension force…

Q: Fi= 3 KN A <作る- 2KNT de 8 c=18 とるcm a= 22 m Fu= 20 KN Eト)=30° FB= 2 KN

A:

Q: 1.0 m 2.0 m 05 m 05 m 20 kN 4 KN 10 kN 4.0 m

A: Given Data: Force (F) = 10 kN

Q: 5 kN 1m 2m E 2 m 3 kN D B 2 m

A: GIVEN DATA- A PLANE TRUSS GIVEN  WE HAVE TO FIND FORCE IN MEMBER BC

Q: 20 kN D 20 kN 20 kN 3 m 10 kN 3 m 3 m A 4 m 4 m E 4 m 4 m B,

A:

Q: З KN 8 kN A 25 kN m 2 m 2 m 2 m 5 kN

A: Note: As per bartleby guidelines for more than one question asked only one question to be solved…

Q: 5 kN 4 m B 5 kN 4 m C D 2 m

A: The free-body diagram of the strut is given as,

Q: G. 620mm 1.8m 1.2m

A: As per honor code and answering guidelines I can answer 1st 3 sub parts at a time.So i answered…

Q: F = 375 N F2 = 500 N 5 3 В. 0.5 m 8 m 6 m - 5 m- 370 F3 = 160 N

A: The given system of forces is as shown below,

Q: F3 = 52 lb 13 12 F1 = 80 lb 25°

A: Given that, The component of forces in the x-direction,

Q: 2.6 kN 2.4 kN-m B A 1.0 m 1.0 m 1.0 m

A: To draw the shear force or bending moment diagram, one should first determine the reaction at the…

Q: 2.5 kN 1.5 kN 3 kN 30 A B. 2m 4m 2m

A: Resolve the two forces along the beam and perpendicular to the beam as shown. Write the x component…

Classification of types of corrosion

Corrosion is described as the process in which a certain element is degraded or deteriorated due to the presence of multiple chemicals in the surrounding. Generally, corrosion happens if all the subatomic particles on a metallic object are oxidized, for example, rust on iron structures. In air or water, metals lose electrons to other particles (like oxygen), leading to the formation of an oxide with the metal.