0.5000 moles of steam at 200°C was chilled in a ultra-low temperature freezer to -90°C. If the heat of vaporization of steam is 540. cal/gram, the heat of fusion of water is 80.0 cal/gram, the specific heat of steam is 0.500 cal/gram-°C, the specific heat of water is 1.000 cal/gram-°C, and the specific heat of ice is 0.500 cal/gram-°C, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie = 4.184 Joules. %3D

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
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0.5000 moles of steam at 200°C was chilled in a ultra-low temperature freezer to -90°C. If the heat of
vaporization of steam is 540. cal/gram, the heat of fusion of water is 80.0 cal/gram, the specific heat of steam is
0.500 cal/gram-°C, the specific heat of water is 1.000 cal/gram-°C, and the specific heat of ice is 0.500
cal/gram-°C, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie = 4.184
Joules.
Transcribed Image Text:0.5000 moles of steam at 200°C was chilled in a ultra-low temperature freezer to -90°C. If the heat of vaporization of steam is 540. cal/gram, the heat of fusion of water is 80.0 cal/gram, the specific heat of steam is 0.500 cal/gram-°C, the specific heat of water is 1.000 cal/gram-°C, and the specific heat of ice is 0.500 cal/gram-°C, how many kJ of energy is released, assuming no energy loss to the environment? 1 calorie = 4.184 Joules.
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