2. The portion of truss shown represents theupper part of a power transmission line tower.f0.60 m The 2.7 kN force is 60° from the vertical. For0.60 m the given loading, determine all zero force1.60 m-221 m-2.21 m-Emembers.1.2 kN H2.7 kN1.20 mt0.60 m10.60 ma. Use the Method of Section to find theforces in members BC, EH and EJ;b.Use the Method of Joints to find the forcesin members BD and DE;-2.97 m1.2 KN1.20 m1.2 kN10.60 mFo.60m Answers:MFBc = 0.9878 kN, T, FEH = 2.9228 kN, C, FEJ =0.5841 kN, C, FBD = 1.3171 kN, T, FDE = 0.3576kN, C1.2 kN1.2 kN

∑ME=0FBD*1.2=FBEsin38.871.32*1.20.6=FBE=2.64 kN (Tension)∑Fx=01.32+2.64cos(38.87)+FCE=0FCE=3.357 kN…

0.60 m the given loading, determine all members. 2.7 kN 1.20 m 1.2 kN H a. Use the Method of Section forces in members BC, EH and B b. Use the Method of Joints to in members BD and DE; L0.60 m 10.60 m -2.97 m- 1.20 m 1.2 kN 1.2 kN 0.60 m f0.60m Answers: FBc = 0.9878 kN, T, FEH = 2.9228 0.5841 kN, C, FBD = 1.3171 kN,* kN, C R V12 kN 1.2 kN %3D

0.60 m the given loading, determine all members. 2.7 kN 1.20 m 1.2 kN H a. Use the Method of Section forces in members BC, EH and B b. Use the Method of Joints to in members BD and DE; L0.60 m 10.60 m -2.97 m- 1.20 m 1.2 kN 1.2 kN 0.60 m f0.60m Answers: FBc = 0.9878 kN, T, FEH = 2.9228 0.5841 kN, C, FBD = 1.3171 kN,* kN, C R V12 kN 1.2 kN %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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