Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im = 0.1 kgm? and the inertia of the second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms². Given the gear transmission efficiency is 90%.

Elements Of Electromagnetics
7th Edition
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NTG = 45
r=30 mm
NTm = 30
driver
a = 2 ms?
2 kg
Figure Q1
Transcribed Image Text:NTG = 45 r=30 mm NTm = 30 driver a = 2 ms? 2 kg Figure Q1
Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and
their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven
gear. The inertia of the gear attached to the motor is Im
= 0.1 kgm² and the inertia of the
second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30
mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms-². Given the gear
transmission efficiency is 90%.
a) Based on the module and number of teeth given, examine the pitch diameter of eachgear.
b) Considering acceleration of load at 2 ms-2, evaluate the torque of the motor toovercome
gears inertia.
c) Considering the 2 kg load, examine the torque required to accelerate the load throughgear system.
d) Suggest the minimum torque of the motor
accelerate the 2 kg load at 2 ms.
Transcribed Image Text:Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im = 0.1 kgm² and the inertia of the second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms-². Given the gear transmission efficiency is 90%. a) Based on the module and number of teeth given, examine the pitch diameter of eachgear. b) Considering acceleration of load at 2 ms-2, evaluate the torque of the motor toovercome gears inertia. c) Considering the 2 kg load, examine the torque required to accelerate the load throughgear system. d) Suggest the minimum torque of the motor accelerate the 2 kg load at 2 ms.
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