0.64 moles of an ideal gas undergoes a couple of change processes that move the system from (P₁, V₁) to (P2, V₂) as shown on the diagram below. Both points share the same temperature, T = 451 K, and P₁ = 1.36 bars, P₂ = 0.63 bars. The two pathways are defined as Pathway 1 + 2- isochoric cooling to (P2, V₁), then isobaric expansion to (P2, V₂). Pathway 3- isothermal expansion directly to (P2, V₂). 3 For the purposes of this problem, you may assume that C₁ = ³R and Cp = R. 2 P↑ (P₁,V₁) To (P₂, V₁) T (3) (2) (P₂, V₂) V a) Find the volumes V₁ and V₂ and compute AV (in L) for the net process. (b) For each of the three paths drawn, calculate AU, AH, and AS. Report the first two in units of kJ, and the last in units of J/K. (c) Since Gibbs energy is a state function, AG is the same for both pathways. Evaluate it for the net process and report it in units of kJ. Note: The temperature at the point (P2, V₁) is different from that of the isotherm, and has been labeled To. You may need to define this temperature in your calculations. Also, for part (c) the absolute entropy content at that same point can be assumed to be 200 J/K.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter12: Thermodynamic Processes And Thermochemistry
Section: Chapter Questions
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0.64 moles of an ideal gas undergoes a couple of change processes that move the system
from (P₁, V₁) to (P2, V₂) as shown on the diagram below. Both points share the same
temperature, T = 451 K, and P₁ = 1.36 bars, P₂ = 0.63 bars. The two pathways are defined as
Pathway 1 + 2- isochoric cooling to (P2, V₁), then isobaric expansion to (P2, V₂).
Pathway 3- isothermal expansion directly to (P2, V₂).
=
For the purposes of this problem, you may assume that Cy
P
(P₁, V₁)
(1)
To
(P₂, V₁)
T
(3)
(2)
3
5
R and Cp = R.
2
(P2, V₂)
V
(a) Find the volumes V₁ and V₂ and compute AV (in L) for the net process.
(b) For each of the three paths drawn, calculate AU, AH, and AS. Report the first two in units
of kJ, and the last in units of J/K.
(c) Since Gibbs energy is a state function, AG is the same for both pathways. Evaluate it for
the net process and report it in units of kJ.
Note: The temperature at the point (P2, V₁) is different from that of the isotherm, and has
been labeled To. You may need to define this temperature in your calculations. Also, for part
(c) the absolute entropy content at that same point can be assumed to be 200 J/K.
Transcribed Image Text:0.64 moles of an ideal gas undergoes a couple of change processes that move the system from (P₁, V₁) to (P2, V₂) as shown on the diagram below. Both points share the same temperature, T = 451 K, and P₁ = 1.36 bars, P₂ = 0.63 bars. The two pathways are defined as Pathway 1 + 2- isochoric cooling to (P2, V₁), then isobaric expansion to (P2, V₂). Pathway 3- isothermal expansion directly to (P2, V₂). = For the purposes of this problem, you may assume that Cy P (P₁, V₁) (1) To (P₂, V₁) T (3) (2) 3 5 R and Cp = R. 2 (P2, V₂) V (a) Find the volumes V₁ and V₂ and compute AV (in L) for the net process. (b) For each of the three paths drawn, calculate AU, AH, and AS. Report the first two in units of kJ, and the last in units of J/K. (c) Since Gibbs energy is a state function, AG is the same for both pathways. Evaluate it for the net process and report it in units of kJ. Note: The temperature at the point (P2, V₁) is different from that of the isotherm, and has been labeled To. You may need to define this temperature in your calculations. Also, for part (c) the absolute entropy content at that same point can be assumed to be 200 J/K.
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