1 2 3 4 5 6 7| -1 0 1 0 0 0 0 2 0 0 2 1 1 8 0 0 1 0 0 -2 1 2 0 0 1 0 4 2 0 0 1 0 0 2 -4 0 0 0 0 1 3.

Q: 1 3 -4 2 0 0 0 0 0 0 0 0 -1 6. 1 -3 7 1 4 -3 0 0

A: Remark:  We know that the maximum number of linearly independent vectors in a matrix is equal to the…

Q: 1 1 1 3 1 k) A =1 2 4. B-0 3 2 2 1 20 1) (1 0 1 2) 5 3 -1 8 2 0 B- -2 -3 -3 -5 0 -1 -2 3 1) A= 4 -3…

A: Please follow the next step.

Q: 2.0k 2.0아 1.5 1.5 1.0 f 1.0 f 0.5 0.5 T3 T3 0.5 1.0 1.5 2.0 2.5 3.0 3.5 0.5 1.0 1.5 2.0 2.5 3.0 3.5

A: Option C is the correct answer.

Q: 1 0 0 0 0 1 0 0 0 0 0 0 0 1 1 A = 1 1 13 0 0 1 0 5 B = 0 0 0 1 0 0 0 3 1 12 2 0 0 1 7 C = 0 0 0 0 1…

A:

Q: i 1 2 0 |11 |12 13 | 14 | 3 4 5 7 8. 12 15 Xj 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0…

A: Here, plot the above data points on the xy - plane and connect them with a smooth curve.

Q: 2 3 0 1 4 0 0 1 2 A = 1

A:

Q: 1.0 12.0 3.0 3.0 -8.0 -2.0 3.0 A = 8.0 2.0 m -12.0 -3.0 3.0

A: Given the matrix A=112303-8-230820m-12-33 Let we take the value of m=-3 A=112303-8-230820-3-12-33…

Q: 1 0 0 0 0 1 2 -6 2 -8 10 1 0 1 0 3 -2 -5 -16 |

A: We have to multiply: 1000012-60010003-22-8-5-16

Q: 57. 1.2" (0.5)* 61. 2 + 2 - 12 = 0 65. 16" + 4** - 3 = 0 58. 0.31+* = 1.72r-1 62. 32 + 3*- 2 = 0 %D…

A:

Q: 1 0 0 0 1 -1 0 0 0 -1 - (Ь.) А — 1 -1 0 0 -1 0 -1 0 0 0 0 -1 1 0 0 1 - 1

A: Given: A=100001-100-11-100-10000-1-11001 To find: Jordan Canonical form of the matrices.

Q: . ʟᴇᴛ x ʙᴇ ᴛʜᴇ ɴᴜᴍʙᴇʀ ᴏꜰ ᴀᴄᴄɪᴅᴇɴᴛꜱ ɪɴ ᴀ ᴘᴀʀᴛɪᴄᴜʟᴀʀ ɪɴᴛᴇʀꜱᴇᴄᴛɪᴏɴ ɪɴ ᴀ ᴡᴇᴇᴋ. ᴛʜᴇ ᴛᴀʙʟᴇ ʙᴇʟᴏᴡ ꜱʜᴏᴡꜱ ᴀ…

A: As per our company guidelines we are supposed to answer only first question. Kindly repost other…

Q: 1 1 0 2 1 1 B = |-1 2 1 1 0 0 1 2

A: We have the given matrix :  B=1102-12111012 First we have to find the basis for the col(B) . Next we…

Q: 3. 4. 5. 0 -1 0 1 2 -3 -1 0 3 5 B: 0 2 0 2 -- [ 011- 01-3 1 -6 2 -4 1 2 5 -4 0 0-3 17 11 030 002 2 0…

A: We have to multiply given Matrix.

Q: 2 6 6 1 0 0 [A|I] = 2 7 6 0 1 0 2 7 7 0 0 1 1 0 01 7 0 -3 1 1 0 0

A:

Q: 1 0 0 6 A 0 1 0 7 0 0 1 1 1 0 0* 0 1 1 0 0 0 0 1 В 1 0 0 4. 0 0 1 5 0 0 0 0 1 0 0 4. 0 0 1 5 0 0 0 0

A: A matrix is in reduced row-echelon form if the following holds: 1) All the leading elements are 1.…

Q: T 3 0 0 ? 0 2 [ 2 2 0 0. 0. 0 2 2 0 2 0 3 3 0 -2 | 2 -2 2 0 3 0 0 0 -1 4 -2 -2 -2 3

A: Explanation of the solution is given below...

Q: Find the real solution(s) of each equation.

A: The solution of an equation is the values to the variable at which we get both sides of the equation…

Q: 1 3 AT – [1,0, 0]" [0, 1] = 2 4 [3 6 0 2 3 4 4 6 1 2 3 4 4 6 1 2

A:

Q: In Problems 49–60, solve each inequality algebraically.

A: “Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: solutions. 1 00 5 7 0 10 1 0 0 0 0 1 1 70 0 0 0 7) 0 0 0 1 0 0 0 2 1 1 1 1 1 0 0 1 0 0 0 0 0 1 0 2 7…

A:

Q: 1 0 1 0 -1 1 0 1 -1 0 0 1 0 -1 0 1]

A:

Q: 2 1 0 1 0 2 [1 2 4 2 4 8 4 0 4 2 o] 2

A:

Q: 0.2 0.1 0.3 0.3 0.6 0.3 43. Р 3D 0.1 0.2 0.2 0.4 0.1 0.2

A: Given:  P=10.20.10.300.30.60.300.10.20.200.40.10.2To find : steady state matrix X of the absorbing…

Q: 12 2 1 (3) 3 승++ (-5)= 1 113 -105 3. (4) (0.85-8금)x(-4) 0.85 - 8 | %3D 20 7. (5) (-2, -0.65) × (-)

A:

Q: In Problems 7–14, find the value of each determinant.

A: 7. We have to find the value of the following determinant: 64-13 Then we get, 64-13=6×3-4×-1=18+4=22…

Q: How do you calculate this equation? Do you use a calculator? How do you get the answer to this…

A: The formula for the pmf of binomial distribution is given as follows:

Q: -5 4 0 1 0 * 0 * 0 1 0. 0. . 1 0. 8. 0. 2 0.

A:

Q: 0 0 0 0 30 0 0 2 0 0 0 0 1 0 0 0 4 Evaluate: 0

A: The determinant of a matrix is found by expanding the determinant along a particular row or column…

Q: [1 2 |4 [2 2 1 1] 4 2 0 2 8 4 4 0 2 2 o]

A: We Know that The rank of a matrix is defined as the maximum number of linearly independent row…

Q: f(x) = 3x? + 8 x = 5 21 6 30 -5 2 | f(x) = x³ – 2x² * = 2 3 f(x) = -x? + 3x + 9 15 4 2 3 *= -6 |…

A: As per our guidelines we are supposed to answer only ? 3 sub- parts ( if there are multiple sub-…

Q: Find the real solutions of each equation. Verify your results using a graphing utility.

A: Given equation is: t4-16=0 Solving we get, t22-42=0⇒t2+4t2-4=0⇒t2+4=0  ;   t2-4=0⇒t2=-4  ;…

Q: Solve the equations

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: 1 1 + 3*5 1 1 n ... 1*3 5*7 (2n-1)*(2n+1) 2n+1

A:

Q: Compute AB by block multiplication, using the indicated partitioning.

A: We will assume the by parts to be some variables so as to carry out easy matrix multiplication.

Q: 1. 0.5 + 1.5 0.2 2. 0.3 · (1.2 – 0.4) 3. (1.2 + 0.5)(1.5 – 0.3) 4. (3.5 + 2.3) + 0.2 5. E-) 6.G-)…

A: 1. 0.5+1.5·0.2=0.5+0.3                       =0.82. 0.3·(1.2-0.4)=0.3·0.8…

Q: 4. у %3D х6 - Зх4 + 5x2 7 2 4 6 8 5. у %3D (x + 10) (2х - 5) 6. у %3D (x3 + 1) (3x2 - 1) 7. у %3D 5x…

A: We have to find the derivative of the following function

Q: 1: = 2 -1 1 2 4 1-3 5-2 1 3 4-2 5 -2 1 3 3 -1 4 -1 2-4-2 7 2 - 4 P = 90 3 4 1 0-45 0 0 0 18 90 90…

A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts which…

Q: 2.0 7.0 10+ -6 2.0 4.6 3.0 7.8 3.0 4.0 8- 4.0 5.8 4.0 2.1 5.0 6.7 5.0 1.4 6.0 4.2 6.0 1.7 2- 2- 7.0…

A:

Q: Use the matrix P to show that the matrices A and A′ are similar.

A:

Q: 3 4 -7 6 3.1 2.4 6.4 2 -2 0 +3 5 2 7 4-1.6 3.8 4 -1.9 5 7 -4 5.3 3.4 -4.8 3 -1 5 1. Determine

A:

Q: В. X2 Χ X2 Χ X2 2 1 3 4 3. 3 5 4. 4. ΣΧΣΧ ΣΧ ΣΧ EX = ΣΧ= ΣΧ2 = 5 Χ

A:

Q: 1 3 5 8 - 37 13) 3 8. 7 Ans. r = 3 0 - 37 0 37

A:

Q: 1 1 3 3 1. 3 3 2 1 1 1. 2 1. 2 1. A 1. 1 3 6 2 1. 4 2 2 2 4 2 1 3.

A:

Q: -2 3 0 71 -1 0 0 0 3 0 0 -1 3 0 00 5 3 2 5 3 0 0 If A = -3 4 5 6 -

A:

Q: 2 30 14 -2 -1 2 -4 1 3 1 11 A = ,A = -7 0 0 0 -2 Select an Answer 3. 10 0 0 0 1 -1 -1 2 0 2 3 A = ,2…

A:

Q: solve the equations using graphicalmethods.

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: 1 -2 0 2 0 0 1 5 0 -3 0 0 0 1 0 0 0 0 1 1

A: Given Augmented Matrix:- 1-2020100150-30000160000001-110 To solve the augmented matrix

Q: Det 0 1 0 0 0 3 4 1 2 Det 1 1 1 00 4 00 Det 1 1 0 %3D 313 [4 1 0 Det 1 1 0 3 10

A: