Arial24...100%Normal text(/+| 1 I 2 l 3 I 4 III|5.8. One way to determine if a relationship is inverse or direct is to find a proportionalityconstant, k, from the data. If this relationship is direct, k P/V. If it is inverse, k = P-V.Calculate k for the seven ordered pairs in your data table (divide and multiply the P and V6 -Chemistry with VernierLAB REPORT: Boyle's LawNAMEDatevalues). Show the answers in the third column of the Data and Calculations table. Whichequation gives roughly the same answer? Does this match your answer from #4?9. How constant were the values for k you obtained in Question 8? Good data may show someminor variation, but the values for k should be relatively constant.10. Using P, V, and k, write an equation representing Boyle's law. Write a verbal statement thatcorrectly expresses Boyle's law. 100%nus (Alt+/)I 21 11DATA AND CALCULATIONSPressureVolume(kPa)(mL)5.8 mL191.3010.8103.4713.384.1315.871.5218.362.5720.855.66PROCESSING THE DATA/CONCLUSION1. If the volume is doulbled from 5.0 mL to 10.0 mL, wpressure? Slhow the pressure values in your answer.

Given: Boyles law and observation table To find: K for the seven observation Solution: Boyles law…

1 8. One way to determine if a relationship is inverse or direct is to find a proportionality constant, k, from the data. If this relationship is direct, k P/V. If it is inverse, k = P-V. Calculate k for the seven ordered pairs in your data table (divide and multiply the P and V

1 8. One way to determine if a relationship is inverse or direct is to find a proportionality constant, k, from the data. If this relationship is direct, k P/V. If it is inverse, k = P-V. Calculate k for the seven ordered pairs in your data table (divide and multiply the P and V

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any â€œdriftâ€ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)
Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdk
Which statements are TRUE regarding internal standards? I. The response factor is calculated by using a mixture containing known amounts of analyte and internal standard and by using detector response to the analyte and the internal standard. II. Internal standards are useful where instrument response or quantity of sample analyzed varies over time. III. Detector response is inversely proportional to concentration. IV. Detector response to analyte and internal standard is assumed to be constant over a range of concentrations A. I, II, and III B. II, III, and IV C. I and II D. I, II, and IV
Chemistry The levels of an organic pollutant (P) in the groundwater at the perimeter of a plant were a cause for concern. A 10 mL sample of the water was taken and the pollutant was extracted with 95% efficiency using 25 mL of diethyl ether. GC was used to analyse the concentration of P in diethyl ether. A calibration curve was plotted for a series of standards of P which yielded the following results: Peak Area Toluene Conc. (µg/ml) 12,000 2.6 23,700 5.0 35,500 7.7 46,800 9.9 31,250 Sample Determine the concentration of P in ppb in the initial groundwater sample.
FT-IR technique can be utilized for the analysis of unknown analytes by matching it with__________. Both choices are correct Commercial library/database Reference standard
1. Which of the following is NOT a true representation of the Lineweaver-Burk equation? Group of answer choices a. y-intercept = -1/Vmax b. x-intercept = -1/Km c. y = 1/V0 d. x = 1/[S] e. slope = Km/Vmax 2. If the y-intercept of a Lineweaver-Burk (double reciprocal) plot = 39.37 (sec/millimole) and the slope = 75.3 L/sec, Vmax equals: Group of answer choices a. 75.3 millimoles/sec. b. 0.0254 millimoles/sec. c. 0.523 millimoles/sec. d. 39.4 millimoles/sec. 3. Which of the following is true regarding allosteric enzyme behavior?Group of answer choices a. Allosteric enzymes are rarely important in the regulation of metabolic pathways. b. An allosteric effector binds reversibly on the surface of the enzyme. c. An hyperbolic representation of the relation initial velocity vs [S] is a specific characteristic of an allosteric enzyme behavior. d. Michaelis-Menten kinetics model the kinetic behavior of allosteric enzymes.
can you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.be
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Example: A GC-FID analysis was conducted on a soil sample containing pollutant X. The following separations were conducted: t (minutes) peak area Injection 1 21.1 ppm Toluene internal Standard 10.11 36,242 33.4 ppm 14.82 45,997 Injection 2 21.1 ppm Toluene Internal Standard 10.05 38,774 unknown concentration X 14.77 39,115 What is the concentration of X in the sample?
A fly ash aerosol of monodisperse particles with a density of 2.0 g/mL and particle diameter of 10.0 mm has a concentration of 1000.0 mg/m3. Calculate the settling velocity in cm/s and the settling rate in g/m2-s. Please answer very soon will give rating surely
Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466