1 A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of d₁ = 157 cm and makes an angle of ₁ = 125° with the positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of ₂ = 33.0° to the positive x axis. Find the magnitude and direction of the second displacement. Step 1 The diagram suggests that ď₂ is larger than either of the other vectors and is in a fourth-quadrant direction. y Ꮎ . Step 2 We use the component meth subtraction. a precise answer. We already know the Step 3 The resultant displacement of the mop is R = ₂ + ď₂ 1 Then d₂ = R-d₁ Substituting, ₂ = (138✔ 138 cm at 33.0°) - (157✔ ant displacement, so the algebra of solving a vector equation will guide us to 157 cm at 125°). a

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 45P
icon
Related questions
Question
A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of
positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of
direction of the second displacement.
Step 1
The diagram suggests that d, is larger than either of the other vectors and is in a fourth-quadrant direction.
2
d₁
Then d₂ = R-d₁
1
Substituting, d
2
y
Step 2
We will use the component method for a precise answer. We already know the resultant displacement, so the algebra of solving a vector equation will guide us to do a
subtraction.
Step 3
The resultant displacement of the mop is R = ď₁ +
1
2
=
=
19₂
R
(138
138 cm at 33.0°) - 157
Step 4
The meaning of the negative sign reverses the direction of the second vector so we can rewrite the previous equation as
(138 cm at 33.0°) + (157 cm at 33
X
The response you submitted has the wrong sign.º),
which, in components, is
d₂ = [138 cos 33
+ 138 sin 125
Your response..differs from the correct answer by more than 100%.°ĵ
+ 157 cos
The response you submitted has the wrong sign.º↑ + 157 sin
Then, evaluating and collecting terms,
d₂=(
or d₂ = (
+ 90)Î + (75.2 -
î–
₁ = 157 cm and makes an angle of ₁ = 125° with the
92 = 33.0° to the positive x axis. Find the magnitude and
157 cm at 125°).
Ĵ) cm.
)Ĵ cm
°ĵ] cm.
Transcribed Image Text:A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of positive x axis. The resultant displacement has a magnitude of R = 138 cm and is directed at an angle of direction of the second displacement. Step 1 The diagram suggests that d, is larger than either of the other vectors and is in a fourth-quadrant direction. 2 d₁ Then d₂ = R-d₁ 1 Substituting, d 2 y Step 2 We will use the component method for a precise answer. We already know the resultant displacement, so the algebra of solving a vector equation will guide us to do a subtraction. Step 3 The resultant displacement of the mop is R = ď₁ + 1 2 = = 19₂ R (138 138 cm at 33.0°) - 157 Step 4 The meaning of the negative sign reverses the direction of the second vector so we can rewrite the previous equation as (138 cm at 33.0°) + (157 cm at 33 X The response you submitted has the wrong sign.º), which, in components, is d₂ = [138 cos 33 + 138 sin 125 Your response..differs from the correct answer by more than 100%.°ĵ + 157 cos The response you submitted has the wrong sign.º↑ + 157 sin Then, evaluating and collecting terms, d₂=( or d₂ = ( + 90)Î + (75.2 - î– ₁ = 157 cm and makes an angle of ₁ = 125° with the 92 = 33.0° to the positive x axis. Find the magnitude and 157 cm at 125°). Ĵ) cm. )Ĵ cm °ĵ] cm.
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

Blurred answer
Knowledge Booster
Vector basics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning