1) A storage tank contains 37.5 kg of carbon dioxide (CO2) at 330 kPa pressure and a temperature of 250 C. (a) What is the volume of the tank? (b) What is the rms velocity of the carbon dioxide molecules? (c) Calulate individually the internal energy of translation, rotation, and vibration of the sample. (d) Assuming the tank has a fixed volume, how much heat would be required to raise the temperture of the sample to 60°C? average translational kinetic energy = (3/2)kT average rotational kinetic energy = (2/2)kŤ = kT average vibrational kinetic energy = (2/2)kT = KT !3! %3D C 12.0 g/mol O 16.0 g/mol

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
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Author:Kreith, Frank; Manglik, Raj M.
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Chapter5: Analysis Of Convection Heat Transfer
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Problem 5.9P: When a sphere falls freely through a homogeneous fluid, it reaches a terminal velocity at which the...
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1) A storage tank contains 37.5 kg of carbon dioxide (CO,) at 330 kPa pressure
and a temperature of 250 C. (a) What is the volume of the tank? (b) What is
the rms velocity of the carbon dioxide molecules? (c) Calulate individually the
internal energy of translation, rotation, and vibration of the sample. (d)
Assuming the tank has a fixed volume, how much heat would be required to
raise the temperture of the sample to 60°C?
average translational kinetic energy = (3/2)kT
average rotational kinetic energy (2/2)kŤ = kT
average vibrational kinetic energy = (2/2)kT = kT
%3D
%3!
( 12,0 g/mol
O 16.0 g/mol
Transcribed Image Text:High 1) A storage tank contains 37.5 kg of carbon dioxide (CO,) at 330 kPa pressure and a temperature of 250 C. (a) What is the volume of the tank? (b) What is the rms velocity of the carbon dioxide molecules? (c) Calulate individually the internal energy of translation, rotation, and vibration of the sample. (d) Assuming the tank has a fixed volume, how much heat would be required to raise the temperture of the sample to 60°C? average translational kinetic energy = (3/2)kT average rotational kinetic energy (2/2)kŤ = kT average vibrational kinetic energy = (2/2)kT = kT %3D %3! ( 12,0 g/mol O 16.0 g/mol
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