1-b. The Virginia Department of Environmental Quality (VDEQ) uses probabilistic moni- toring to regulate the water quality of streams in the Commonwealth of Virginia. Of the 120 Eastern Virginia Sites (group 1), 17 do not meet minimum requirements. Of the 80 units sam- pled in Western Virginia Sites (group 2), 24 do not meet minimum requirements. Assume the data can be treated as independent simple random samples. (3). The hypotheses to test that the proportions of streams that fail to meet minimum require- ments in the two areas are equal or not is a. Ho : P1 = P2 versus H. : P1 < P2- b. Ho : p1 = P2 versus Ha : p1 > p2- c. Ho : P1 = P2 versus Ha : p1 # P2- d. Ho : P1 = P2 versus H. : î1 # ê2- (4). The value of the z statistic for testing equality of the proportions of streams that fail to meet minimum requirements in the two areas are equal or not is a. z= -2,62 b. z = -2.72 c. z = -1.96 d. z = -2.33. (5). The researcher tests the following hypotheses Ho : pi = P2 versus H : p1 # p2. The 90% confidence interval is a. –0.158 ± 0.096 b. -0.158 ±0.099 c. -0.158 ±0.077 d. -0.158 ±0.075

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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Author:HOLT MCDOUGAL
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Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
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1-b. The Virginia Department of Environmental Quality (VDEQ) uses probabilistic moni-
toring to regulate the water quality of streams in the Commonwealth of Virginia. Of the 120
Eastern Virginia Sites (group 1), 17 do not meet minimum requirements. Of the 80 units sam-
pled in Western Virginia Sites (group 2), 24 do not meet minimum requirements. Assume the
data can be treated as independent simple random samples.
(3). The hypotheses to test that the proportions of streams that fail to meet minimum require-
ments in the two areas are equal or not is
a. Ho : P1 = P2 versus H. : P1 < P2.
b. Ho : p1 = p2 versus Ha : P1 > P2-
c. Ho : P1 = P2 versus H. : P1 + P2.
d. Ho : P1 = P2 versus H. : P1 + p2-
(4). The value of the z statistic for testing equality of the proportions of streams that fail to
meet minimum requirements in the two areas are equal or not is
a. z = -2,62 b. z = -2.72 c. z = -1.96 d. z = -2.33.
(5). The researcher tests the following hypotheses Ho : p1 = p2 versus H. : p1 # p2. The 90%
confidence interval is
a. -0.158 + 0.096
b. -0.158 + 0.099
c. -0.158 ±0.077
d. -0.158 +0.075
Transcribed Image Text:1-b. The Virginia Department of Environmental Quality (VDEQ) uses probabilistic moni- toring to regulate the water quality of streams in the Commonwealth of Virginia. Of the 120 Eastern Virginia Sites (group 1), 17 do not meet minimum requirements. Of the 80 units sam- pled in Western Virginia Sites (group 2), 24 do not meet minimum requirements. Assume the data can be treated as independent simple random samples. (3). The hypotheses to test that the proportions of streams that fail to meet minimum require- ments in the two areas are equal or not is a. Ho : P1 = P2 versus H. : P1 < P2. b. Ho : p1 = p2 versus Ha : P1 > P2- c. Ho : P1 = P2 versus H. : P1 + P2. d. Ho : P1 = P2 versus H. : P1 + p2- (4). The value of the z statistic for testing equality of the proportions of streams that fail to meet minimum requirements in the two areas are equal or not is a. z = -2,62 b. z = -2.72 c. z = -1.96 d. z = -2.33. (5). The researcher tests the following hypotheses Ho : p1 = p2 versus H. : p1 # p2. The 90% confidence interval is a. -0.158 + 0.096 b. -0.158 + 0.099 c. -0.158 ±0.077 d. -0.158 +0.075
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