1) Discuss the following solution  The highest and lowest temperature is given as : HT LT 24 14 27 15 25 15 27 16 29 16 31 17 29 15 28 16 28 17 29 18 Sum - 277 Sum - 159 Average - 27710=27.7 Average - 15910=15.9 From the table, Mean of high temperature is 27.7 degree Mean of low temperature is 15.9 degree Solution - 2 2) Median : The data has been ascendingly orderd as : HT LT 24 14 25 15 27 15 27 15 28 16 28 16 29 16 29 17 29 17 31 18 From the table values,  Median of high temperature : MdHT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=28+0.528-28=28 Median of high temperature is 28 degree Median of low temperature : MdLT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=16+0.516-16=16 Median of low temperature is 16 degree

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.2: Representing Data
Problem 24PFA
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1) Discuss the following solution 

The highest and lowest temperature is given as :

HT LT
24 14
27 15
25 15
27 16
29 16
31 17
29 15
28 16
28 17
29 18
Sum - 277 Sum - 159
Average - 27710=27.7 Average - 15910=15.9

From the table,

Mean of high temperature is 27.7 degree

Mean of low temperature is 15.9 degree

Solution - 2

2) Median :

The data has been ascendingly orderd as :

HT LT
24 14
25 15
27 15
27 15
28 16
28 16
29 16
29 17
29 17
31 18

From the table values, 

Median of high temperature :

MdHT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=28+0.528-28=28

Median of high temperature is 28 degree

Median of low temperature :

MdLT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=16+0.516-16=16

Median of low temperature is 16 degree

 

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