1) Discuss the following solution The highest and lowest temperature is given as : HT LT 24 14 27 15 25 15 27 16 29 16 31 17 29 15 28 16 28 17 29 18 Sum - 277 Sum - 159 Average - 27710=27.7 Average - 15910=15.9 From the table, Mean of high temperature is 27.7 degree Mean of low temperature is 15.9 degree Solution - 2 2) Median : The data has been ascendingly orderd as : HT LT 24 14 25 15 27 15 27 15 28 16 28 16 29 16 29 17 29 17 31 18 From the table values, Median of high temperature : MdHT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=28+0.528-28=28 Median of high temperature is 28 degree Median of low temperature : MdLT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=16+0.516-16=16 Median of low temperature is 16 degree
1) Discuss the following solution The highest and lowest temperature is given as : HT LT 24 14 27 15 25 15 27 16 29 16 31 17 29 15 28 16 28 17 29 18 Sum - 277 Sum - 159 Average - 27710=27.7 Average - 15910=15.9 From the table, Mean of high temperature is 27.7 degree Mean of low temperature is 15.9 degree Solution - 2 2) Median : The data has been ascendingly orderd as : HT LT 24 14 25 15 27 15 27 15 28 16 28 16 29 16 29 17 29 17 31 18 From the table values, Median of high temperature : MdHT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=28+0.528-28=28 Median of high temperature is 28 degree Median of low temperature : MdLT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=16+0.516-16=16 Median of low temperature is 16 degree
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.2: Representing Data
Problem 24PFA
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Question
1) Discuss the following solution
The highest and lowest temperature is given as :
HT | LT |
24 | 14 |
27 | 15 |
25 | 15 |
27 | 16 |
29 | 16 |
31 | 17 |
29 | 15 |
28 | 16 |
28 | 17 |
29 | 18 |
Sum - 277 | Sum - 159 |
Average - 27710=27.7 | Average - 15910=15.9 |
From the table,
Mean of low temperature is 15.9 degree
Solution - 2
2) Median :
The data has been ascendingly orderd as :
HT | LT |
24 | 14 |
25 | 15 |
27 | 15 |
27 | 15 |
28 | 16 |
28 | 16 |
29 | 16 |
29 | 17 |
29 | 17 |
31 | 18 |
From the table values,
Median of high temperature :
MdHT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=28+0.528-28=28
Median of high temperature is 28 degree
Median of low temperature :
MdLT=n+12thitems=10+12thitems=112thitems=5.5thitems=5thitems+0.56thitems-5thitems=16+0.516-16=16
Median of low temperature is 16 degree
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