1) Each of the following statements about Y86-64 are true. Which of them is an attribute that makes Y86-64 more RISC-like? Select all that apply. the OPq instructions operate only on registers there are few ways to specify instruction operands in Y86-64 • simpler instructions can take up less space than more complicated ones Y86-64 has only 18 instructions (counting conditional moves and conditional jumps each as one instruction) Y86-64 has instructions like pop which modify two registers, allowing for shorter programs

1) Each of the following statements about Y86-64 are true. Which of them is an attribute that makes Y86-64 more RISC-like? Select all that apply. the OPq instructions operate only on registers there are few ways to specify instruction operands in Y86-64 • simpler instructions can take up less space than more complicated ones Y86-64 has only 18 instructions (counting conditional moves and conditional jumps each as one instruction) Y86-64 has instructions like pop which modify two registers, allowing for shorter programs

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 15VE: A(n) ________________ instruction always alters the instruction execution sequence. A(n)...

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The following is an 8051 instruction:CJNE A,#'Q',AHEADa. What is the opcode for this instruction?b. How many bytes long is this instruction?c. Explain the purpose of each byte of this instruction.d. How many machine cycles are required to execute this instruction?e. If an 8051 is operating from a 10 MHz crystal, how long does this instructiontake to execute?
Please answer this question and provide the explanation Assume the values of %ecx is 0x00000005 and %edx is 0x00000003. What would be the value of %ecx and %edx after performing the following instruction? 0x5555555461a <+0>: leal (%ecx, %edx, 8), %edx %ecx = 0x00000005, %edx = 0x0000003A %ecx = 0x00000005, %edx = 0x00000018 %ecx = 0x00000005, %edx = 0x00000030 %ecx = 0x00000005, %edx = 0x00000003 %ecx = 0x00000005, %edx = 0x0000001D %ecx = 0x00000005, %edx = 0x00000040 %ecx = 0x00000055, %edx = 0x0000001D %ecx = 0x00000005, %edx = 0x0000002A %ecx = 0x00000005, %edx = 0x00000025 %ecx = 0x00000005, %edx = 0x00000035
For the following MIPS assembly instructions what is the corresponding C statement? Assume that variables f,g,h,i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4. Assume that the base address of the arrays A and B are in registers $s6 and $s7, respectively. Add comments for each line to describe what each instruction does. addi $t0, $s6, 4 # $t0 = &A+4 = &A[1] add $t1, $s6, $zero # sw $t1, 0($t0) # lw $t0, 0($t0) # add $s0, $t1, $t0 #
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For the MIPS assembly instructions below, what is thecorresponding C statement? Assume that the variables f, g, h, i, and j areassigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume thatthe base address of the arrays A and B are in registers $s6 and $s7,respectively. Note: for each line of MIPS code below, write the respective Ccode. After that, write the corresponding C code for the MIPS.sll $t0, $s0, 2add $t0, $s6sll $t1, $s1, 2 add $t1, $s7, $t1lw $s0, 0($t0)addi $t2, $t0, 4lw $t0, 0($t2)add $t0, $t0, $s0sw $t0, 0($t1)
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