Question
Asked Nov 6, 2019

The uniform concrete block has a weight of 300 lb. The coefficients of static friction are μA = 0.2, μB = 0.3, and between the concrete block and the floor, μ = 0.4. (Figure 1)

Determine the smallest couple moment that can be applied to the 190-lb wheel that will cause impending motion.

-1 ft
5 ft
М
1.5 ft
A
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-1 ft 5 ft М 1.5 ft A

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check_circleExpert Solution
Step 1

Given data as per question

weight of the block=300 lb
weight of the wheel-190lb
static friction u, 0.2
friction between concrete block and floory
0.4
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weight of the block=300 lb weight of the wheel-190lb static friction u, 0.2 friction between concrete block and floory 0.4

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Step 2

Considering free body diagram of the wheel

W
ND
-fa
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W ND -fa

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Step 3
ΣΕ-0
ΣΕ-0
N, +FW
NI+N
N.+μ.μ.Ν. w
a
N
1+H
a
190
1+(0.2xo.3)
N 179.2466lb
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ΣΕ-0 ΣΕ-0 N, +FW NI+N N.+μ.μ.Ν. w a N 1+H a 190 1+(0.2xo.3) N 179.2466lb

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