Question
Asked Mar 3, 2020
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1) Given the following:
1)
2 HBr(g) = H2(g) + Br2(g)
Kc = 7.04 x 10-2
Find the value of the equilibrium constant for the following equilibrium reaction
1/2 H2(g) + 1/2 Br2(g) = HBr(8)
Kc = ?
A) 3.52 x 10-2
B) 0.265
C) 3.77
D) 28.4
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1) Given the following: 1) 2 HBr(g) = H2(g) + Br2(g) Kc = 7.04 x 10-2 Find the value of the equilibrium constant for the following equilibrium reaction 1/2 H2(g) + 1/2 Br2(g) = HBr(8) Kc = ? A) 3.52 x 10-2 B) 0.265 C) 3.77 D) 28.4

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Expert Answer

Step 1

The equilibrium constant, Kc for a reaction is given as :

Chemistry homework question answer, step 1, image 1

Step 2

The given reaction is :

2 HBr (g) ↔ H2 (g) + Br2 (g)          Kc1 = 7.04 × 10-2 

 The equilibrium constant, Kc1 for this reaction can be expressed as :

Chemistry homework question answer, step 2, image 1

Step 3

Again, the given reaction is :

½ H2 (g) + ½ Br2 (g) ↔ HBr (g)          Kc2 = ?

 

The equilibrium constant, Kc2 for this reaction can be expressed as :

Chemistry homework question answer, step 3, image 1

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