1) Position of a particle as a function of time is given by the expression: x(s)= 5sti +(-5s² + -2s³)j Determine the velocity as a function of time: v(s) = i +, Determine the acceleration as a function of time: a(s) =, .j Determine the magnitude of the velocity at t=2.2s, Iv(t=2.2)l = _m/s

1) Position of a particle as a function of time is given by the expression: x(s)= 5sti +(-5s² + -2s³)j Determine the velocity as a function of time: v(s) = i +, Determine the acceleration as a function of time: a(s) =, .j Determine the magnitude of the velocity at t=2.2s, Iv(t=2.2)l = _m/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 2P

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Concept explainers

Proper Length

The theory of special relativity explains the connection between space and time to objects that move in a straight line at a constant speed. The objects move at the speed of light. When an object approaches light speed, its mass is endless and cannot move faster than light. The most crucial postulate of Einstein's special relativity is that the laws of nature do not change in each frame of reference.

Question

Can someone help please? thanks

1) Position of a particle as a function of time is given by the expression:
x(s)= 5s*i +(-5s² + -2s°)j
Determine the velocity as a function of time:
v(s) = .
i +
j
Determine the acceleration as a function of time:
a(s)
i +
j
Determine the magnitude of the velocity at t=2.2s,
Iv(t=2.2)l =_
_m/s

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