1) Since E0 (Fe3 + / Fe2 +) = + 0.77 V, E0 (Fe2 + / Feo) = - 0.44 V and E0 (MnO4- / Mn2 +) = +1.51 V Fe / Fe3 + (0.01M) // pH = 3; MnO4- (0.10M); Mn2 + (0.01M) / Pt Write down the anode, cathode and total battery reactions of the battery. Calculate the cell potential at a temperature of 25 degrees Celsius and the equilibrium constant of the spontaneous reaction in the cell with the Gibbs Free Energy Change.
1) Since E0 (Fe3 + / Fe2 +) = + 0.77 V, E0 (Fe2 + / Feo) = - 0.44 V and E0 (MnO4- / Mn2 +) = +1.51 V Fe / Fe3 + (0.01M) // pH = 3; MnO4- (0.10M); Mn2 + (0.01M) / Pt Write down the anode, cathode and total battery reactions of the battery. Calculate the cell potential at a temperature of 25 degrees Celsius and the equilibrium constant of the spontaneous reaction in the cell with the Gibbs Free Energy Change.
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.31QAP
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1) Since E0 (Fe3 + / Fe2 +) = + 0.77 V, E0 (Fe2 + / Feo) = - 0.44 V and E0 (MnO4- / Mn2 +) = +1.51 V
Fe / Fe3 + (0.01M) // pH = 3; MnO4- (0.10M); Mn2 + (0.01M) / Pt
Write down the anode, cathode and total battery reactions of the battery. Calculate the cell potential at a temperature of 25 degrees Celsius and the equilibrium constant of the spontaneous reaction in the cell with the Gibbs Free Energy Change.
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