(1) The element with an electron configuration of 1s²2s22p°3s 3p°4s²3d is in group and period (2) The element with an electron configuration of 1s²2s2p° is in group |and period
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- Copper atoms. (a) What is the average mass of one copper atom? (b) Students in a college computer science class once sued the college because they were asked to calculate the cost of one atom and could not do it. But you are in a chemistry course, and you can do this. (See E. Felsenthal, Wall Street Journal, May 9, 1995.) If the cost of 2.0-mm diameter copper wire (99.9995% pure] is currently 41.70 for 7.0 g, what is the cost of one copper atom?Consider an atom of 64Zn. (a) Calculate the density of the nucleus in grams per cubic centimeter, knowing that the nuclear radius is 4.8 106 nm and the mass of the 64Zn atom is 1.06 1022 g. (Recall that the volume of a sphere is [4/3] 3.) (b) Calculate the density of the space occupied by the electrons in the zinc atom, given that the atomic radius is 0.125 nm and the electron mass is 9.11 1028 g. (c) Having calculated these densities, what statement can you make about the relative densities of the parts of the atom?a. Classify the following elements as metals or nonmetals: Mg Si Rn Ti Ge Rn Au B Am Bi At Br b. The distinction between metals and nonmetals is really not a clear one. Some elements, called metalloids, are intermediate in their properties. Which of these elements would you reclassify as metalloids? What other elements in the periodic table would you expect to be metalloids?
- There are 1.699 1022 atoms in 1.000 g of chlorine. Assume that chlorine atoms are spheres of radius 0.99 and that they are lined up side by side in a 0.5-g sample. How many miles in length is the line of chlorine atoms in the sample?The early alchemists used to do an experiment in which water was boiled for several days in a sealed glass container. Eventually. some solid residue would appear in die bottom of the flask, which was interpreted to mean that some of the water in the flask had been converted into earth. When Lavoisier repeated this experiment, he found that the water weighed the same before and after heating, and the mass of die flask plus the solid residue equaled the original mass of the flask. Were the alchemists correct? Explain what really happened. (This experiment is described in the article by A. F. Scott in Scientific American, January 1984.)Average Atomic Weight Part 1: Consider the four identical spheres below, each with a mass of 2.00 g. Calculate the average mass of a sphere in this sample. Part 2: Now consider a sample that consists of four spheres, each with a different mass: blue mass is 2.00 g, red mass is 1.75 g, green mass is 3.00 g, and yellow mass is 1.25 g. a Calculate the average mass of a sphere in this sample. b How does the average mass for a sphere in this sample compare with the average mass of the sample that consisted just of the blue spheres? How can such different samples have their averages turn out the way they did? Part 3: Consider two jars. One jar contains 100 blue spheres, and the other jar contains 25 each of red, blue, green, and yellow colors mixed together. a If you were to remove 50 blue spheres from the jar containing just the blue spheres, what would be the total mass of spheres left in the jar? (Note that the masses of the spheres are given in Part 2.) b If you were to remove 50 spheres from the jar containing the mixture (assume you get a representative distribution of colors), what would be the total mass of spheres left in the jar? c In the case of the mixture of spheres, does the average mass of the spheres necessarily represent the mass of an individual sphere in the sample? d If you had 80.0 grams of spheres from the blue sample, how many spheres would you have? e If you had 60.0 grams of spheres from the mixed-color sample, how many spheres would you have? What assumption did you make about your sample when performing this calculation? Part 4: Consider a sample that consists of three green spheres and one blue sphere. The green mass is 3.00 g, and the blue mass is 1.00 g. a Calculate the fractional abundance of each sphere in the sample. b Use the fractional abundance to calculate the average mass of the spheres in this sample. c How are the ideas developed in this Concept Exploration related to the atomic weights of the elements?
- Constant Composition of Compounds Two samples of sugar are decomposed into their constituent elements. One sample of sugar produces 18.0 g carbon, 3.0 g hydrogen, and 24.0 g oxygen; the other sample produces 24.0 g carbon, 4.0 g hydrogen, and 32.0 g oxygen. Find the ratio of carbon to hydrogen and the ratio of oxygen to hydrogen for each of the samples, and show they are consistent with the law of constant composition.Two elements, R and Q, combine to form two binary compounds. In the first compound, 14.0 g of R combines with 3.00 g of Q. In the second compound, 7.00 g of R combines with 4.50 g of Q. Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is RQ, what is the formula of the first compound?1. The radius of a rhodium atom is 134 pm. How many rhodium atoms would have to be laid side by side to span a distance of 1.70 mm? 2. The mass of a single uranium atom is 4.70×10-22 grams. How many uranium atoms would there be in 196 milligrams of uranium?
- F2(g)+2e-→2F-(aq) 2.866 O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076 Co3+(aq)+e-→Co2+(aq) 1.92 H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776 Ce4+(aq)+e-→Ce3+(aq) 1.72 Au+(aq)+e-→Au(s) 1.692 PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691 MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507 Au3+(aq)+3e-→Au(s) 1.498 Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36 Cl2(g)+2e-→2Cl-(aq) 1.358 O2(g)+4H+(aq)+4e-→2H2O(l) 1.229 MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224 2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195 Br2(l)+2e-→2Br-(aq) 1.066 VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991 HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983 NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957 2Hg2+(aq)+2e-→Hg22+(aq) 0.92 Hg2+(aq)+2e-→Hg(l) 0.851 Ag+(aq)+e-→Ag(s) 0.800 Hg22+(aq)+2e-→2Hg(l) 0.797 Fe3+(aq)+e-→Fe2+(aq) 0.771 O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695 MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595 I2(s)+2e-→2I-(aq) 0.536 Cu+(aq)+e-→Cu(s) 0.521 O2(g)+2H2O(l)+4e-→4OH-(aq)…Convert atomic mass of Ca to g. atomic mass of Ca is 40.08 amu Group of answer choices A.) 3.00 x 10exp-18 g B.) 1.20 x 10exp22 g C.) 6.653 x 10 exp-23 g D.) 6.653 x10exp-22 g1.Determine the number of protons, electrons,and neutrons present in(a) 32P (b) 98Mo (c) 44Ca (d) 3H (e) 158Gd (f ) 212Bi 2. The atomic masses of 35Cl (75.53%) and 37Cl (24.47%) are 34.968 amu and 36.956 amu, respectively. Calculate the average atomic mass of chlorine. The percentages in parentheses denote the relative abundances. 3. The atomic masses of 6Li and 7Li are 6.0151 amu and 7.0160 amu, respectively. Calculate the natural abundances of these two isotopes. The average atomic mass of Li is 6.941 amu. 4. One isotope of a metallic element has mass number 65 and 35 neutrons in the nucleus. The cation derived from the isotope has 28 electrons. Write the symbol for this cation. 5. One isotope of a nonmetallic element has mass number 127 and 74 neutrons in the nucleus. The anion derived from the isotope has 54 electrons. Write the symbol for this anion.