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Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Note: write the half reaction as it would actually occur at the cathode. 0 yes, there is a minimum. no minimum yes, there is a maximum. no maximum 0 E = red Ov 0 E Ov red =

Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Note: write the half reaction as it would actually occur at the cathode. 0 yes, there is a minimum. no minimum yes, there is a maximum. no maximum 0 E = red Ov 0 E Ov red =

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 16P
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F2(g)+2e-→2F-(aq) 2.866
O3(g)+2H+(aq)+2e-→O2(g)+H2O(l) 2.076
Co3+(aq)+e-→Co2+(aq) 1.92
H2O2(aq)+2H+(aq)+2e-→2H2O(l) 1.776
Ce4+(aq)+e-→Ce3+(aq) 1.72
Au+(aq)+e-→Au(s) 1.692
PbO2(s)+4H+(aq)+SO42-(aq)+2e-→PbSO4(s)+2H2O(l) 1.691
MnO4-(aq)+8H+(aq)+5e-→Mn2+(aq)+4H2O(l) 1.507
Au3+(aq)+3e-→Au(s) 1.498
Cr2O72-(aq)+14H+(aq)+6e-→2Cr3+(aq)+7H2O(l) 1.36
Cl2(g)+2e-→2Cl-(aq) 1.358
O2(g)+4H+(aq)+4e-→2H2O(l) 1.229
MnO2(s)+4H+(aq)+2e-→Mn2+(aq)+2H2O(l) 1.224
2IO3-(aq)+12H+(aq)+10e-→I2(s)+6H2O(l) 1.195
Br2(l)+2e-→2Br-(aq) 1.066
VO2+(aq)+2H+(aq)+e-→VO2+(aq)+H2O(l) 0.991
HNO2(aq)+H+(aq)+e-→NO(g)+H2O(l) 0.983
NO3-(aq)+4H+(aq)+3e-→NO(g)+2H2O(l) 0.957
2Hg2+(aq)+2e-→Hg22+(aq) 0.92
Hg2+(aq)+2e-→Hg(l) 0.851
Ag+(aq)+e-→Ag(s) 0.800
Hg22+(aq)+2e-→2Hg(l) 0.797
Fe3+(aq)+e-→Fe2+(aq) 0.771
O2(g)+2H+(aq)+2e-→H2O2(aq) 0.695
MnO4-(aq)+2H2O(l)+3e-→MnO2(s)+4OH-(aq) 0.595
I2(s)+2e-→2I-(aq) 0.536
Cu+(aq)+e-→Cu(s) 0.521
O2(g)+2H2O(l)+4e-→4OH-(aq) 0.401
Cu2+(aq)+2e-→Cu(s) 0.342
HSO4-(aq)+3H+(aq)+2e-→H2SO3(aq)+H2O(l) 0.172
SO42-(aq)+4H+(aq)+2e-→SO2(g)+2H2O(l) 0.172
Cu2+(aq)+e-→Cu+(aq) 0.153
Sn4+(aq)+2e-→Sn2+(aq) 0.151
2H+(aq)+2e-→H2(g) 0.000
Fe3+(aq)+3e-→Fe(s) -0.037
Pb2+(aq)+2e-→Pb(s) -0.126
CrO42-(aq)+4H2O(l)+3e-→Cr(OH)3(s)+5OH-(aq) -0.13
Sn2+(aq)+2e-→Sn(s) -0.138
N2(g)+5H+(aq)+4e-→N2H5+(aq) -0.214
Ni2+(aq)+2e-→Ni(s) -0.257
Co2+(aq)+2e-→Co(s) -0.28
PbSO4(s)+H+(aq)+2e-→Pb(s)+HSO4-(aq) -0.359
Cd2+(aq)+2e-→Cd(s) -0.403
Cr3+(aq)+e-→Cr2+(aq) -0.407
Fe2+(aq)+2e-→Fe(s) -0.447
Cr3+(aq)+3e-→Cr(s) -0.744
Zn2+(aq)+2e-→Zn(s) -0.762
2H2O(l)+2e-→H2(g)+2OH-(aq) -0.828
Cr2+(aq)+2e-→Cr(s) -0.913
N2(g)+4H2O(l)+4e-→4OH-(aq)+N2H4(aq) -1.16
Mn2+(aq)+2e-→Mn(s) -1.185
Al3+(aq)+3e-→Al(s) -1.676
Be2+(aq)+2e-→Be(s) -1.847
Sc3+(aq)+3e-→Sc(s) -2.077
Mg2+(aq)+2e-→Mg(s) -2.372
Na+(aq)+e-→Na(s) -2.71
Ca2+(aq)+2e-→Ca(s) -2.868
Sr2+(aq)+2e-→Sr(s) -2.899
Ba2+(aq)+2e-→Ba(s) -2.912
K+(aq)+e-→K(s) -2.931
Li+(aq)+e-→Li(s) -3.040
A certain half-reaction has a standard reduction potential E -1.11 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must red provide at least 1.50 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.
Transcribed Image Text:A certain half-reaction has a standard reduction potential E -1.11 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must red provide at least 1.50 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.
Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Note: write the half reaction as it would actually occur at the cathode. Oyes, 0 there is a minimum. no minimum yes, there is a maximum. no maximum 0 = E Ov red 0 E red = Ov
Transcribed Image Text:Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. By using the information in the ALEKS Data tab, write a balanced equation describing a half reaction that could be used at the cathode of this cell. Note: write the half reaction as it would actually occur at the cathode. Oyes, 0 there is a minimum. no minimum yes, there is a maximum. no maximum 0 = E Ov red 0 E red = Ov
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