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1- x,(n) = {0" sln| – 3

1- x,(n) = {0" sln| – 3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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- 4 sns-1 1sng4 otherwise (-1 1- x, (n) = {In| - 3sns3 otherwise X2(n) = }+1 Let x, (n) and x,(n) defined above. Sketch the following signals. a) x,(2n) b) x, (n/2) c) x2(1 – n) d) x, (n – 2) + x,(n + 2) e) x1(n + 2). x2 (n– 2) f) x1 (n).x2(-2 - n) 2- Determine whether the following signals are periodic. If they are periodic find the fundamental period. a) x(n)=cos (un) b) x(n)=cos (rn). sin un) c) x{n)=(-1)n° d) x(n)=cos(2n) 3- Evaluate the convolution sums given below. a) y(n)=u(n) * u(n-3) b) y(n)=(1/2)".u(n-2) * u(n) c) y(n)=u(n) * E 8(n-2p) p-0 d) x(n)=26(n – 1) – 0.58(n – 2) d1) x(n) * h(n) h(n)=-8(n – 2) – 0.58(n – 1) + 3 8(n – 3) d2) x(-n) * h(n) 4- Determine the outputs and impulse responses described by the following difference equations with input and initial conditions as specified: a) y(n) -y(n-2)=x(n-1) y(-1)=1, y(-2)=0, x(n)=u(n) b) y(n) -y(n-1)- y(n-2)=x(n)+x(n-1) y(-1)=2, y(-2)=-1, x(n)=2"u(n)
Transcribed Image Text:- 4 sns-1 1sng4 otherwise (-1 1- x, (n) = {In| - 3sns3 otherwise X2(n) = }+1 Let x, (n) and x,(n) defined above. Sketch the following signals. a) x,(2n) b) x, (n/2) c) x2(1 – n) d) x, (n – 2) + x,(n + 2) e) x1(n + 2). x2 (n– 2) f) x1 (n).x2(-2 - n) 2- Determine whether the following signals are periodic. If they are periodic find the fundamental period. a) x(n)=cos (un) b) x(n)=cos (rn). sin un) c) x{n)=(-1)n° d) x(n)=cos(2n) 3- Evaluate the convolution sums given below. a) y(n)=u(n) * u(n-3) b) y(n)=(1/2)".u(n-2) * u(n) c) y(n)=u(n) * E 8(n-2p) p-0 d) x(n)=26(n – 1) – 0.58(n – 2) d1) x(n) * h(n) h(n)=-8(n – 2) – 0.58(n – 1) + 3 8(n – 3) d2) x(-n) * h(n) 4- Determine the outputs and impulse responses described by the following difference equations with input and initial conditions as specified: a) y(n) -y(n-2)=x(n-1) y(-1)=1, y(-2)=0, x(n)=u(n) b) y(n) -y(n-1)- y(n-2)=x(n)+x(n-1) y(-1)=2, y(-2)=-1, x(n)=2"u(n)
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