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- Please answer atleast 4 sub-parts. Thank you.Lactated Ringer’s/5% Dextrose solution contains: 6 g/L of Sodium Chloride (NaCl MW 58.5) 3.1 g/L of Sodium Lactate (C3H5O3Na MW 112) 0.3g/L of Potassium Chloride (KCl MW 74.5) 0.2g/L of Calcium Chloride (CaCl2•2H2O MW 147) 50g/L of Dextrose (C6H12O6 MW 180) You receive an order to increase the Potassium ion concentration to 0.045 mEq/mL. How many mL of 14.9% Potassium chloride injection should be added to 1L of the above solution to increase the potassium ion concentration to 0.045 mEq/mL ____________________mL 14.9% KCl injectionhttps://m.youtube.com/watch?v=vM1SP346XBc&list=PLeJOSNLNZfHubfLdq0kOayASeUllMOGn4&index=4 I watched this the lecture video over and over and I am allowed to work with someone but I am having trouble with part B and I provided the YouTube link of the data or video attached to this lab
- Calculate the solubility of lead(II) sulfate (Ksp = 2.53x10-8) in a 0.0034 M solution of sodium sulfate. Give your answer to three sig. figs. and in exponential form (e. g. 1.23E-3).Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdkAleks data for PbCO3 is 7.40 x 10^-14.
- By the use of Henderson Hasselbalch equation; pH = pKa + log{[acetate ion]/[acetic acid]} 4.5 = 4.75 + log{[0.10 M]/[acetic acid]} -0.25 = log{[0.10 M]/[acetic acid]} [Acetic acid] = 0.10 M/ 10-0.25 [Acetic acid] = 0.10 M/0.56 [Acetic acid] = 0.1786 M Moles of sodium acetate dissolved in 250 mL buffer solution = 0.10 M× (250mL/1000mL) × 1L = 0.025 mol Weight (w) of sodium acetate (purity 100%) dissolved to prepare 250 mL of solution with buffer concentration of 0.10 M is calculate as follow; w100% = 0.025 mol × 82.0343 g/mol = 2.051 g Weight (w) of sodium acetate (purity 99%) is calculate as follow; w99% = 2.051 g× (100/99) = 2.072 g What was the volume of 6.12 M acetic acid HC2H3O2 needed to prepare the 250 mL acetic acid/acetate ion buffer solution required in this part? Show your calculations.https://www.youtube.com/watch?v=2EQznGPZY5AHexanoic acid was added to an immiscible biphasic solvent sysem, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D1) of hexanoic acid in CCl4 with respect to water.
- If 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)Calculate the amount of phycocyanin in Sample 1 in mg where A620 = 0.193 and A650 = 0.095, taking into account the dilution factor of 100 ul, and the total volume of extract 45ml. Note your answer to 2 decimal places.2I– (aq) + H2O2 (aq) + 2H3O + (aq) → I2 (aq) + 4H2O (l) (slow) C6H8O6 (aq) + 2H2O (l) + I2 (aq) → C6H6O6 (aq) + 2H3O + (aq) + 2I– (aq) (very fast) I2 (aq) + I– (aq) ⇌ I – 3 (aq) I3- (aq) + starch → blue I3- · starch complex (aq) (fast) (a) A 0.100 L solution is prepared with initial concentrations of 4.0 × 10−3 M iodine I2 , 8.0×10−3 M iodide I– , and 5.0×10−3 M ascorbic acid C6H8O6 . After the second reaction goes to completion, what will the molar concentrations of iodide and ascorbic acid in the solution be?