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1. A 0.2700 g sample of impure NazCO3 required 24.12 mL of 0.1684 M HCI and a back- titration with 2.96 mL of NaOH solution. The volume ratio of the acid to the base is 1.250. Calculate the % Na2CO3 in the sample.

1. A 0.2700 g sample of impure NazCO3 required 24.12 mL of 0.1684 M HCI and a back- titration with 2.96 mL of NaOH solution. The volume ratio of the acid to the base is 1.250. Calculate the % Na2CO3 in the sample.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
Section4.7: Molar Concentration
Problem 4.10E: A sample of sodium chloride, NaCl, weighing 0. 0678 g is placed in a 25.0-mL volumetric flask....
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EXERCISE II - 1. A 0.2700 g sample of impure Na2CO3 required 24.12 mL of 0.1684 M HCI and a back- titration with 2.96 mL of NaOH solution. The volume ratio of the acid to the base is 1.250. Calculate the % Na2CO3 in the sample. 2 A sample of material contains for its active components NaOH, NazCO3, NaHCO3, or compatible mixtures of these. Two samples, each weighing 1.000 g, are dissolved in H20. To one sample phenolphthalein is added and the solution is titrated cold with 1.038 N acid, of which 17.96 mL is required. The other sample is titrated cold, with methyl orange as indicator, and 21.17 mL of the same acid is required. What alkalis are present, and what is the percentage of each in the original sample? 3. Analysis of a mixture consisting of NaOH + Na2CO3 + inert matter gives the following data: Sample portions are titrated. With one portion, an end point with phenolphthalein is obtained in cold solution, with 44.52 mL of 0.5000 N HCI. The other portion requires 46.53 mL of the acid for an end point with methyl orange. Calculate the percentage composition of the original sample. 10.00 g. Its aqueous solution is diluted to 250.0 mL and two separate 25.00 mL %3D 4. A 0.500 g sample consisting of Na2CO3, NaHCO3, and inert materials was dissolved in sufficient water to give 250.0 mL of solution. A 25.00 mL aliquot of this solution was boiled with 50.00 mL of 0.01255 M HCI. Titration of the excess HCI to a phenolphthalein endpoint required 2.34 ml of 0.01063 M NaOH. The carbonate species in the second 25.00 mL aliquot was precipitated with an excess of BaCl2 and treated with 25.00 mL of the NaOH. Titration of the excess base required 7.63 mL of the standard acid. Calculate % Na,CO3 and NaHCO3 in the sample.
Transcribed Image Text:EXERCISE II - 1. A 0.2700 g sample of impure Na2CO3 required 24.12 mL of 0.1684 M HCI and a back- titration with 2.96 mL of NaOH solution. The volume ratio of the acid to the base is 1.250. Calculate the % Na2CO3 in the sample. 2 A sample of material contains for its active components NaOH, NazCO3, NaHCO3, or compatible mixtures of these. Two samples, each weighing 1.000 g, are dissolved in H20. To one sample phenolphthalein is added and the solution is titrated cold with 1.038 N acid, of which 17.96 mL is required. The other sample is titrated cold, with methyl orange as indicator, and 21.17 mL of the same acid is required. What alkalis are present, and what is the percentage of each in the original sample? 3. Analysis of a mixture consisting of NaOH + Na2CO3 + inert matter gives the following data: Sample portions are titrated. With one portion, an end point with phenolphthalein is obtained in cold solution, with 44.52 mL of 0.5000 N HCI. The other portion requires 46.53 mL of the acid for an end point with methyl orange. Calculate the percentage composition of the original sample. 10.00 g. Its aqueous solution is diluted to 250.0 mL and two separate 25.00 mL %3D 4. A 0.500 g sample consisting of Na2CO3, NaHCO3, and inert materials was dissolved in sufficient water to give 250.0 mL of solution. A 25.00 mL aliquot of this solution was boiled with 50.00 mL of 0.01255 M HCI. Titration of the excess HCI to a phenolphthalein endpoint required 2.34 ml of 0.01063 M NaOH. The carbonate species in the second 25.00 mL aliquot was precipitated with an excess of BaCl2 and treated with 25.00 mL of the NaOH. Titration of the excess base required 7.63 mL of the standard acid. Calculate % Na,CO3 and NaHCO3 in the sample.
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