1. A 250–g piece of gold is at 19 °C, 5192 J of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature. (A. 160.99 B. 179.99 C. 59.25) 2. How much heat is absorbed by 100 g of ice at -10⁰C to become water at 20⁰C? • Specific heat: Water (Ice) = 2,090 J/Kg•⁰C, Water (Liquid) = 4,186 J/Kg•⁰C • Latent heat of fusion (Water) = 3.33 x105 J/Kg ( A. 4..38 X 10 ^ 4 B. 4.38 X 10 ^ 7 C. 4.76 X 10 ^ 5)
1. A 250–g piece of gold is at 19 °C, 5192 J of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature. (A. 160.99 B. 179.99 C. 59.25) 2. How much heat is absorbed by 100 g of ice at -10⁰C to become water at 20⁰C? • Specific heat: Water (Ice) = 2,090 J/Kg•⁰C, Water (Liquid) = 4,186 J/Kg•⁰C • Latent heat of fusion (Water) = 3.33 x105 J/Kg ( A. 4..38 X 10 ^ 4 B. 4.38 X 10 ^ 7 C. 4.76 X 10 ^ 5)
Chapter1: Temperature And Heat
Section: Chapter Questions
Problem 91P: Calculate the rate of heat conduction out of the human body, assuming that the core internal...
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1. A 250–g piece of gold is at 19 °C, 5192 J of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature.
(A. 160.99 B. 179.99 C. 59.25)
2. How much heat is absorbed by 100 g of ice at -10⁰C to become water at 20⁰C?
• Specific heat: Water (Ice) = 2,090 J/Kg•⁰C, Water (Liquid) = 4,186 J/Kg•⁰C
• Latent heat of fusion (Water) = 3.33 x105 J/Kg
( A. 4..38 X 10 ^ 4 B. 4.38 X 10 ^ 7 C. 4.76 X 10 ^ 5)
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