1. A boy on a 20-m high platform throws a ball at a distance of 5 m. At what speed is the ball thrown? (See the diagram) Solution: Given: dx Find : Vox (Vox = 4) Since d = 5 m, then we need to find the time t, yet from d = X y 5 m; horizontal distance dy = 20 m; vertical distance t = √ Hence, Vox = dx t /2(20) 9.8 5m sec. m/s gta, or or t = √ 2dy g 20m 5 m

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Chapter6: Motion In Two Dimensions
Section: Chapter Questions
Problem 84A
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1. A boy on a 20-m high platform throws a ball at a distance of 5 m. At what speed is the
ball thrown? (See the diagram)
Solution: Given dx =
dy
Find : Vox (Vox =)
t = v
Since d = 5 m, then we need to find the time t, yet from d = gt²,
x
y
Hence, Vox =
dx
t
5 m
20 m
[2(20)
9.8
5m
horizontal distance
vertical distance
sec.
m/s
or t = √ 2dy
| 201
g
20m
Hot Why?
5 m
Transcribed Image Text:1. A boy on a 20-m high platform throws a ball at a distance of 5 m. At what speed is the ball thrown? (See the diagram) Solution: Given dx = dy Find : Vox (Vox =) t = v Since d = 5 m, then we need to find the time t, yet from d = gt², x y Hence, Vox = dx t 5 m 20 m [2(20) 9.8 5m horizontal distance vertical distance sec. m/s or t = √ 2dy | 201 g 20m Hot Why? 5 m
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