1. a) Let y =x2 +3 for 05x54. Find a number c that satisfies the conclusion of the Mean Value Theorem and fill in the blanks below with the points. Then sketch the secant line and corresponding tangent line on the given graph. (the tangent line must be parallel to the secant line) Here is a video as a reminder from Calc. I: https://youtu.be/KdqreAb-44M f(x): Ay m = Ax The slope of the line tangent to y = x2 +3 at the point ( ) is equal to the slope of the %3D secant line passing thorough the points ( ) and ( b) Fill in the blanks for the secant line above. Ax = f'(c) = _ Find the length of the line segment with the distance formula. Round to 2 decimal places. V(Ax)2 + (Ay)² = V(Ax)² + (Axf'(c))² D = %3D

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
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1. a) Let y = x² + 3 for 0 s xS4. Find a number c that satisfies the conclusion of the Mean Value Theorem and fill
in the blanks below with the points. Then sketch the secant line and corresponding tangent line on the given graph.
(the tangent line must be parallel to the secant line) Here is a video as a reminder from Calc. I:
https://youtu.be/KdqreAb-44M
f"(x) =
Ay
m3D
Ax
The slope of the line tangent to y = x² + 3 at the point (
) is equal to the slope of the
%3D
secant line passing thorough the points
) and (
b) Fill in the blanks for the secant line above.
Ax =
f'(c) =
%3D
%3D
Find the length of the line segment with the distance formula. Round to 2 decimal places.
D = (Ax)² + (Ay)² = /(Ax)² + (Axf'(c))² :
%3D
c) Approximate the length of the curve y = x² + 3 for 0 < x< 4 by dividing the curve into 2-equal line segments. I
have placed the endpoints on the graph below. Find the length of the 2-line segments using the steps above , and add
those distances to approximate the curve length. Draw those lines bellow and label each with their length.
%3D
15
10
f'(c,) =
D,=
(2 decimal places)
%3D
Secant line #1: Ax =
Secant line #2: Ax =
f'(c2) =
D2=
(2 decimal places)
%3D
Approximation of curve length:
(2 decimal places)
1
I3I
Transcribed Image Text:1. a) Let y = x² + 3 for 0 s xS4. Find a number c that satisfies the conclusion of the Mean Value Theorem and fill in the blanks below with the points. Then sketch the secant line and corresponding tangent line on the given graph. (the tangent line must be parallel to the secant line) Here is a video as a reminder from Calc. I: https://youtu.be/KdqreAb-44M f"(x) = Ay m3D Ax The slope of the line tangent to y = x² + 3 at the point ( ) is equal to the slope of the %3D secant line passing thorough the points ) and ( b) Fill in the blanks for the secant line above. Ax = f'(c) = %3D %3D Find the length of the line segment with the distance formula. Round to 2 decimal places. D = (Ax)² + (Ay)² = /(Ax)² + (Axf'(c))² : %3D c) Approximate the length of the curve y = x² + 3 for 0 < x< 4 by dividing the curve into 2-equal line segments. I have placed the endpoints on the graph below. Find the length of the 2-line segments using the steps above , and add those distances to approximate the curve length. Draw those lines bellow and label each with their length. %3D 15 10 f'(c,) = D,= (2 decimal places) %3D Secant line #1: Ax = Secant line #2: Ax = f'(c2) = D2= (2 decimal places) %3D Approximation of curve length: (2 decimal places) 1 I3I
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9781133382119
Author:
Swokowski
Publisher:
Cengage