1. A potassium vapor sign consists of K atoms which give off violet light (I = 425.4 nm). a. Calculate the frequency for this wavelength. b. Calculate the JE when only one atom gives off light and when 0.333 moles of atoms give off light simultaneously. (c = 2.9979 x 10° m/s, h = 6.626 x 10-34 J*s) [7.047 x 104 hz] [4.670 x 10-19 J] [93.6 kJ]

Chemistry & Chemical Reactivity
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Chapter6: The Structure Of Atoms
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Problem 70IL: A solution of KMnO4 absorbs light at 540 nm (page 206). What is the frequency of the light absorbed?...
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1. A potassium vapor sign consists of K atoms which give off violet light
(O = 425.4 nm). a. Calculate the frequency for this wavelength. b.
Calculate the E when only one atom gives off light and when 0.333
moles of atoms give off light simultaneously. (c = 2.9979 x 10 m/s, h =
6.626 x 10-34 J*s)
[7.047 x 1014 hz]
[4.670 x 10-1º J]
[93.6 kJ]
Transcribed Image Text:1. A potassium vapor sign consists of K atoms which give off violet light (O = 425.4 nm). a. Calculate the frequency for this wavelength. b. Calculate the E when only one atom gives off light and when 0.333 moles of atoms give off light simultaneously. (c = 2.9979 x 10 m/s, h = 6.626 x 10-34 J*s) [7.047 x 1014 hz] [4.670 x 10-1º J] [93.6 kJ]
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