1. A shaft made of steel having an ultimate strength of Su is finished by grinding the surface. The diameter of the shaft is d. The shaft is loaded with a fluctuating zero-to-maximum torque. % Su = 1200; % ultimate strength (MPa) % Sy = 800; % yield strength (MPa) % d = 8; % diameter of the shaft (mm) % kS = 0.8; % surface factor kS %3D % kG = 1; % size (gradient) factor kG % N = 75*10^3; % cycles 1.2 For N=75000 cycles and repeated loads (zero-to-maximum), from constant life fatigue diagram, determine alternating stress (MPa)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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1. A shaft made of steel having an ultimate strength of Su is finished by grinding the surface.
The diameter of the shaft is d.
The shaft is loaded with a fluctuating zero-to-maximum torque.
% Su = 1200; % ultimate strength (MPa)
% Sy = 800; % yield strength (MPa)
% d = 8;
% diameter of the shaft (mm)
% kS = 0.8; % surface factor kS
% kG = 1;
% size (gradient) factor kG
% N = 75*10^3; % cycles
1.2 For N=75000 cycles and repeated loads (zero-to-maximum), from constant life fatigue diagram,
determine alternating stress (MPa)
Transcribed Image Text:1. A shaft made of steel having an ultimate strength of Su is finished by grinding the surface. The diameter of the shaft is d. The shaft is loaded with a fluctuating zero-to-maximum torque. % Su = 1200; % ultimate strength (MPa) % Sy = 800; % yield strength (MPa) % d = 8; % diameter of the shaft (mm) % kS = 0.8; % surface factor kS % kG = 1; % size (gradient) factor kG % N = 75*10^3; % cycles 1.2 For N=75000 cycles and repeated loads (zero-to-maximum), from constant life fatigue diagram, determine alternating stress (MPa)
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