What is the answer to numbers 1, 3 and 4? 1. Calculate AH for the following equation PbCl216) +Cl2)------> PBCI,(0)AH ?????Given : 1. Pbs) +Cl2ig)------> PbCl, (d)AH f = -359.4 kJ2. Pb () =2 Cl2n------> PBCI4 (1)AHf = -329.3 kJ «%3D 3. Supply the nuclei needed in the alpha emission17 8 0-<>4. Beta emission7534 Se-->

(1) Given data is as follows: PbCl2(s) + Cl2(g) → PbCl4(l) ∆H=? 1. Pb(s) + Cl2(g) → PbCl2(s)…

Answered: 1. Calculate AH for the following…

1. Calculate AH for the following equation PbCl215) +Cl2@) PbClą(1) AH ????? ---- Given: 1. Pb + Cl2e) ------> PbCl2 (d) AH f = -359.4 kJ 2. Pb (s =2 Cl2) ------> PbCIA (1) AHf = -329.3 kJ.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter3: Using Spreadsheets In Analytical Chemistry

Section: Chapter Questions

Problem 3.4QAP

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Concept explainers

Polymerization Kinetics

Polymerization is a chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that diverge in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes. Polymerization is generally classified into step-growth and chain polymerization. Polymers are categorized into linear polymer and cross-linked polymers that are produced either by condensation or additional polymerization.

Question

What is the answer to numbers 1, 3 and 4?

1. Calculate AH for the following equation PbCl216) +Cl2)
------> PBCI,(0)
AH ?????
Given : 1. Pbs) +Cl2ig)
------> PbCl, (d)
AH f = -359.4 kJ
2. Pb () =2 Cl2n
------> PBCI4 (1)
AHf = -329.3 kJ «
%3D

3. Supply the nuclei needed in the alpha emission
17 8 0
-<>
4. Beta emission
75
34 Se
-->

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